Answer:
What is the question to this
Step-by-step explanation:
Answer: Option <span>C. To get system B, the second equation in system A was replaced by the sum of that equation and the first equation multiplied by -3. The solution to system B will be the same as the solution to system A.
First equation of system A multiplied by -3:
(-3)(x+6y=5)
(-3)(x)+(-3)(6)=(-3)(5)
-3x-18=-15
Sum of the second equation of system A and the first equation multiplied by -3:
(-3x-18)+(3x-7y)=(-15)+(-35)
-3x-18+3x-7y=-15-35
-25y=-50
System B
x+6y=5
-25y=-50 </span>
Answer:
The 3rd set
Step-by-step explanation:
The first set has a range of 6, not 5
The second set has a range of 5, but not a mean of 5
The third set has both a mean and a range of 5
Answer:
y/2
Step-by-step explanation:
x+3=y+2
------ --------
3 2
Using cross products
2(x+3) = 3(y+2)
Distribute
2x+6 = 3y+6
Subtract 6 from each side
2x+6-6 = 3y+6-6
2x= 3y
Divide each side by 2
2x/2 = 3y/2
x = 3/2 y
We want to find x/3
Divide each side by 3
x/3 = 3/2 y * 1/3
x/3 = 1/2 y
