Hello,
When you have an inscribed quadrilateral, the opposite sides are supplementary.
So you can write and solve the following equation.
x + 6x + 19 = 180
7x + 19 = 180
7x = 161
x = 23
Now, plug in 23 for X and we will find the measurement of B.
6(23) + 19
138 + 19
157
The measure of angle B is 157 degrees. (The picture is not drawn to scale)
Good luck,
MrEQ
Answer:
D
Step-by-step explanation:
I'm assuming all of (x^2+9) is in the denominator. If that assumption is correct, then,
One possible answer is ![f(x) = \frac{4}{x}, \ \ g(x) = x^2+9](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B4%7D%7Bx%7D%2C%20%20%5C%20%5C%20g%28x%29%20%3D%20x%5E2%2B9)
Another possible answer is ![f(x) = \frac{4}{x+9}, \ \ g(x) = x^2](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B4%7D%7Bx%2B9%7D%2C%20%5C%20%5C%20g%28x%29%20%3D%20x%5E2)
There are many ways to do this. The idea is that when we have f( g(x) ), we basically replace every x in f(x) with g(x)
So in the first example above, we would have
![f(x) = \frac{4}{x}\\\\f( g(x) ) = \frac{4}{g(x)}\\\\f( g(x) ) = \frac{4}{x^2+9}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B4%7D%7Bx%7D%5C%5C%5C%5Cf%28%20g%28x%29%20%29%20%3D%20%5Cfrac%7B4%7D%7Bg%28x%29%7D%5C%5C%5C%5Cf%28%20g%28x%29%20%29%20%3D%20%5Cfrac%7B4%7D%7Bx%5E2%2B9%7D)
In that third step, g(x) was replaced with x^2+9 since g(x) = x^2+9.
Similar steps will happen with the second example as well (when g(x) = x^2)