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Blababa [14]
3 years ago
11

PLEASE HELP!!!

Mathematics
1 answer:
jenyasd209 [6]3 years ago
5 0
The standard formula is: distance = speed x time. From this, we know that speed = distance/time and that time = distance/speed. 

<span>a. If r = speed, then r = distance/time. From the information presented in "a", you cannot calculate Roy's speed. </span>

<span>b, c. Because the time is the limiting value in the question, use the "time" version of the formula: time = distance / speed </span>

<span>Because Roy must be at the ceremony in "less than or equal to" 2 hours, we set up an inequality. </span>
<span>2 <= distance / speed (which = r) </span>
<span>therefore, 2 <= distance / r </span>

<span>Because Roy has already travelled 30 miles, he has only 120 miles remaining. </span>
<span>2 <= 120 / r </span>

<span>Solve for "speed": </span>
<span>2r <= 120 </span>
<span>r <= 60 </span>
<span>You must be careful about how you interpret this answer. Remember hat "r" is the MINIMUM speed which solves the equation. Therefore, to make it to the wedding on time, Roy must drive at least 60 mph.
Sourced from yahoo.</span>
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3 0
3 years ago
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1.Anthony has decided to purchase a $19,000 car. He plans to put 20% down toward the purchase and to finance the rest at a 6.8%
Nikitich [7]
<h2>First step/Equation</h2>

Answer:

 $362.57

Step-by-step explanation:

A suitable calculator or finance app can find the monthly payment for you. This result comes from a TI-84 calculator.

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The second attachment shows the parameters of the payment function. With 20% down, Anthony is only financing 80% of the price of his car. Of course, there are 12 months in a year, so 4 years worth of payments will be 48 payments. The calculator uses negative values for amounts you pay.

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2 years ago
Write the equation x2+24x+60=0 in the form (x+p)2=q
navik [9.2K]

Answer:

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Step-by-step explanation:

x^2+24x+60=0

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3 years ago
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Margarita [4]
Check the picture below.

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\bf ~~~~~~~~~~~~\textit{middle point of 2 points }&#10;\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ -2 &,& -4~) &#10;%  (c,d)&#10;&&(~ 3 &,& 8~)&#10;\end{array}\qquad&#10;%   coordinates of midpoint &#10;\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{3-2}{2}~~,~~\cfrac{8-4}{2} \right)\implies \left( \frac{1}{2}~,~2 \right)\impliedby center

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ -2 &,& -4~) &#10;%  (c,d)&#10;&&(~ 3 &,& 8~)&#10;\end{array}~~~ &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;d=\sqrt{[3-(-2)]^2+[8-(-4)]^2}\implies d=\sqrt{(3+2)^2+(8+4)^2}&#10;\\\\\\&#10;d=\sqrt{25+144}\implies d=\sqrt{169}\implies d=13\qquad\qquad \qquad  \stackrel{radius}{\frac{13}{2}}

\bf \textit{equation of a circle}\\\\ &#10;(x- h)^2+(y- k)^2= r^2&#10;\qquad &#10;center~~(\stackrel{\frac{1}{2}}{ h},\stackrel{2}{ k})\qquad \qquad &#10;radius=\stackrel{\frac{13}{2}}{ r}&#10;\\\\\\&#10;\left( x-\frac{1}{2} \right)^2+(y-2)^2=\left( \frac{13}{2} \right)^2\implies \left( x-\frac{1}{2} \right)^2+(y-2)^2=\frac{169}{4}

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