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Blababa [14]
3 years ago
11

PLEASE HELP!!!

Mathematics
1 answer:
jenyasd209 [6]3 years ago
5 0
The standard formula is: distance = speed x time. From this, we know that speed = distance/time and that time = distance/speed. 

<span>a. If r = speed, then r = distance/time. From the information presented in "a", you cannot calculate Roy's speed. </span>

<span>b, c. Because the time is the limiting value in the question, use the "time" version of the formula: time = distance / speed </span>

<span>Because Roy must be at the ceremony in "less than or equal to" 2 hours, we set up an inequality. </span>
<span>2 <= distance / speed (which = r) </span>
<span>therefore, 2 <= distance / r </span>

<span>Because Roy has already travelled 30 miles, he has only 120 miles remaining. </span>
<span>2 <= 120 / r </span>

<span>Solve for "speed": </span>
<span>2r <= 120 </span>
<span>r <= 60 </span>
<span>You must be careful about how you interpret this answer. Remember hat "r" is the MINIMUM speed which solves the equation. Therefore, to make it to the wedding on time, Roy must drive at least 60 mph.
Sourced from yahoo.</span>
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Write the equation of the line that satisfies the following conditions:
eduard

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a. y=-x+-5

b. y=\frac{4}{3}x+\frac{5}{3}

Step-by-step explanation:

to solve part a we have the slope of the line and a point, so we use the point-slope equation

y=m(x-x_{1})+y_{1}

where m is the slope: m=-1, and (x_{1},y_{1}) is the point, so in this case the point is (0,-5) thus x_{1}=0 and y_{1}=-5.Thus the equation is:

y=-1(x-0)+(-5)

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And for part b we have two points. With the two points we can find the slope and then use the point-slope equation again.

To find the slope we use:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

for the points (x_{1},y_{1}) and (x_{2},y_{2}). Since we have the poits: (1,3) and (-2,-1)

x_{1}=1\\y_{1}=3\\x_{2}=-2\\y_{2}=-1

Thus, the slope:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{-1-3}{-2-1}

m=\frac{-4}{-3}

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and now using the point-slope equation:

y=m(x-x_{1})+y_{1}

y=\frac{4}{3}(x-1)+3\\y=\frac{4}{3}x-\frac{4}{3} +3\\y=\frac{4}{3}x+\frac{5}{3}

7 0
3 years ago
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