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gladu [14]
3 years ago
9

Find the next three terms of each sequence

Mathematics
1 answer:
Shalnov [3]3 years ago
4 0

Answer:

i dont know how to do percentages and stuff and thats what number 9 is its adding 60% i hope this helps im sorry if it doesnt

Step-i dont kby-step explanation:


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how many times as much is the number of students at Pengrove university has the number of students at Allentown College?
svp [43]
The answer would be: D-100. The reasoning of this is because if you take 3 X 10 to the third power and did the exponent (10 to the third power in this case) and multiplied it you would obviously get 1,000 for an answer. Then would would do 1,000 X 3 to get 3,000.
5 0
3 years ago
z 5 ​ − z+2 2z+4 ​ =−3 space, startfraction, 5, divided by, z, end fraction, minus, start fraction, 2, z, plus, 4, divided by, z
yan [13]

Answer:

The sum of all the possible values for z that satisfy the above equation is -5.

Step-by-step explanation:

The given equation is

\frac{5}{z}-\frac{2z+4}{z+2}=-3

We need to find the sum of all the possible values for z that satisfy the above equation.

The given equation can be rewritten as

\frac{5}{z}-\frac{2(z+2)}{z+2}=-3

Cancel out common factors.

\frac{5}{z}-2=-3

Add 2 on both sides.

\frac{5}{z}-2+2=-3+2

\frac{5}{z}=-1

5=-z

Multiply both sides by -1.

-5=z

Only z=-5 satisfy the given equation.

Therefore the sum of all the possible values for z that satisfy the above equation is -5.

8 0
3 years ago
Factorize completely the following algebra expression :<br>81x^4-16y^8​
ohaa [14]
Here’s your answer the A/= it means the answer is okay.

6 0
3 years ago
A mule deer can run one over four of a mile in 25 seconds. At this rate, which expression can be used to determine how fast a mu
geniusboy [140]
Speed (v) = distance (d) / time (t)
so either the second or third. if this is realistic deer can't run 100 miles per hour so is say the second initially but to check what is .25miles/25s convert to hours. (3600 seconds in an hour) so .25*3600=900 then 900miles/25hour= 36miles/ hour.
7 0
3 years ago
How do I solve this problem?
nexus9112 [7]
Subtract the second equation from the first equation.
x = -1
Plug -1 back in to either equation and solve for y.
3(-1) + y =-10
-3 + y = -10
Add 3 to both sides
y = -7
CHECK
3(-1) -7 = -10
2(-1) -7 = -9
(-1, -7)
5 0
3 years ago
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