That part is the median, which is 57.
Let
be the side of the triangle and
be the side of the square.
Let
be the perimeter of the triangle and
be the perimeter of the square.
We have the following relationship:

Which finally implies

This equation has no solution
Answer:
Our system of equations is:
We are looking for x
Let's express y using x
Replace x in the second equation with the result
- 4y-4x²-12x = -7
- 4(-2x-1)-4x²-12x = -7
- -8x-4-4x²-12x = -7
- -8x-4x²-12x = -7+4
- -4x²-20x = -3
- -4x²-20x+3 = 0 multiply by -1 to get rid of the - signs with x
- 4x²+20x-3=0
4x²+20x+3=0 is a quadratic equation
Let Δ be our discriminant
Δ= 20²-4*4*(-3)
Δ=448 > 0 so we have two solutions for x
let x and x' be the solutions
- x =
= -5.145 ≈ -5.15 - x'=
= 0.145≈ 0.15
so the solutions are:
-5.15 and 0.15