Let the side of the garden alone (without walkway) be x.
Then the area of the garden alone is x^2.
The walkway is made up as follows:

1) four rectangles of width 2 feet and length x, and
2) four squares, each of area 2^2 square feet.

The total walkway area is thus x^2 + 4(2^2) + 4(x*2).

We want to find the dimensions of the garden. To do this, we need to find the value of x.

Let's sum up the garden dimensions and the walkway dimensions:

x^2 + 4(2^2) + 4(x*2) = 196 sq ft

x^2 + 16 + 8x = 196 sq ft

x^2 + 8x - 180 = 0

(x-10(x+18) = 0

x=10 or x=-18. We must discard x=-18, since the side length can't be negative. We are left with x = 10 feet.

The garden dimensions are (10 feet)^2, or 100 square feet.

4 0

3 years ago

1.What is the value of log3 729?

xxMikexx [17]

I believe the value of log3 729 is 6