Answer:
20
Step-by-step explanation:
10+10+10+10=40
40/2=20
Let's call the two numbers
and
.
Given these variables, we can say:
, based on the first sentence in the problem.
Also, remember that the reciprocal of a number is simply 1 divided by the number. Thus, we can say that:

To solve, we can simply substitute
in for
in the second equation and solve.


- Get terms on the left side to a common denominator for easier addition


- Cross multiplication (
)


- Subtract
from both sides of the equation

- Factor left side of the equation

Now, notice that we have found two solutions, but the problem is only asking for one. This <em>likely </em>means that one of our solutions is extraneous. Let's take a look. Remember that the smaller positive number is equal to 14 less than the larger number. However,
,
Since
is not positive in this case,
is not a solution.
Thus,
is our only solution. In this case,
,
which means that the smaller number is 14 and the larger number is 28.
We can rewrite the expression under the radical as

then taking the fourth root, we get
![\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cleft%28%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%29%5E4%7D%3D%5Cleft%7C%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%7C)
Why the absolute value? It's for the same reason that

since both
and
return the same number
, and
captures both possibilities. From here, we have

The absolute values disappear on all but the
term because all of
,
and
are positive, while
could potentially be negative. So we end up with

The answer is 8
Here's why:

The exponents are subtracted one from another when divided.

We can look at the problem this way:

Since we have the power of -1 on the 3, we apply this rule:

Also this rule because we have the power of 1 on the 6:

Then we get this:

We apply the rule:

We get this: