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tester [92]
3 years ago
11

Drag each value or expression to the correct location on the equations and sentences. Each value and expression can be used more

than once, but not all values and expressions will be used.
Gary works at a bakery, and he needs to select a rectangular cookie sheet with an area of 192 square inches. The area of the cookie sheet is represented by the expression given below.

Complete the given statements, and find the width of the cookie sheet.

x^2+4x
Step 1: x^2+4x=192
Step 2: x(x+__)=192 Length is X. The width is__.
Step 3: x^2+4x-192=0
Step 4: (x+__)(x-12)=0
Because the length can't be__, the length is 12 and the width is __.

Options: 12, 4, x, x+4, -16, 16, x+12, x^2

Mathematics
2 answers:
sveticcg [70]3 years ago
8 0

Answer: The width of the rectangle will be 16 unit.

Explanation: Since, Given- 192 square unit is the area of the rectangle.

but again, according to the the area is represent by the expression x^2+4x

Then, Steps will be- Step 1:x^2+4x= 192

Step2:x(x+4) = 192, where x is the length of the rectangle. And the width is x+4.

Step3:  x^2+4x-192=0

Step4: (x+16)(x-12)=0

Because the lenght can not be negative, the lenght is 12 and width is 16.

so, option 4th will be right.

Nadusha1986 [10]3 years ago
7 0

That is the answer to your question.

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-x - y when x = -12 and y =2
kap26 [50]

Answer:

10

Step-by-step explanation:

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5 0
3 years ago
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Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?
photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326

What is the probability that they are both queens?

P = \frac{D}{T} = \frac{6}{1326} = 0.0045

0.45% probability that they are both queens.

4 0
3 years ago
the sum of independent normally distributed random variables is normally distributed with mean equal to the sum of the individua
vazorg [7]

The probability that x is between 420 and 460 is 0.25778

The sum of independent normally distributed random variables is normally distributed with mean equal to the sum of the individual means and variance equal to the sum of the individual variances.

so, the mean would be,

μ = 100 + 150 + 200

μ = 450

and standard deviation would be,

σ = 15+ 20 + 25

σ = 60

We need to find the probability that x is between 420 and 460.

P(420 < x < 460)

= P( 420 -  μ < x -  μ < 460 -  μ)

= P((420 -  μ)/σ < (x - μ)/σ < (460 -  μ)/σ)

= P((420 -  450)/60 < Z < (460 -  450)/60)

= P (-1/2 < Z < 1/6)

= P(-0.5<x<0.167)

= 0.25778

Therefore, the probability is P(420 < x < 460) = 0.25778

Learn more about the probability here:

brainly.com/question/11234923

#SPJ4

8 0
1 year ago
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