The law of cosines is
c= square root of a^2 + b^2 - 2ab cos c
the law of sines is
a = b(sin a /sin b)
Answer:
The required result is proved with the help of angle bisector theorem.
Step-by-step explanation:
Given △ABD and △CBD, AE and CE are the angle bisectors. we have to prove that 
Angle bisector theorem states that an angle bisector of an angle of a Δ divides the opposite side in two segments that are proportional to the other two sides of triangle.
In ΔADB, AE is the angle bisector
∴ the ratio of the length of side DE to length BE is equal to the ratio of the line segment AD to the line segment AB.
→ (1)
In ΔDCB, CE is the angle bisector
∴ the ratio of the length of side DE to length BE is equal to the ratio of the line segment CD to the line segment CB.
→ (2)
From equation (1) and (2), we get
Hence Proved.
Answer:
-11/2
Step-by-step explanation:
because that's the answer
Just borrow from the 7 and take the 1 to the 2 and that will make it as 12 so then you subtract 12 - 4 and the answer will be 1,180
The correct answer would be C) CBA-EFD