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3 years ago

46. ANALYZE Is it possible for two points

Mathematics

1 answer:

s2008m [1.1K]3 years ago

8 0

Answer:

The answer to this question is simply NO. There is exactly one line through any two points and exactly one plane through any three points not on the same line. Therefore, any two points on the prism must be collinear and coplanar. ...

Step-by-step explanation:

We have been asked that:

is it possible for two points collinear nor coplanar?

<u>Collinear points:</u>

Collinear points are points that lie on the same line.

<u>Coplanar points:</u>

Coplanar points are points that lie on the same plane.

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If f(x)=2^6x -19, what is the value of f(1)

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Answer:

Step-by-step explanation:

f(x)=2^6x-19

f(1)=2^(6(1))-19=2^(6)-19=2^6-19=64-19=45

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2 years ago

Answer?? please answer

Maru [420]

Answer:

The y-value of Function A when x = 2 is GREATER than the y-value of Function B when x = 2

Step-by-step explanation:

✔️Find the equation of Function A:

To do this, find the y-intercept (b) and slope (m):

Slope (m) = change in y/change in x

Using (4, 13) and (5, 17),

Slope (m) = (17 - 13)/(5 - 4) = 4/1

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To find b, substitute (x, y) = (4, 13) and m = 4 into y = mx + b

13 = 4(4) + b

13 = 16 + b

13 - 16 = b

b = -3

To write the equation for Function A, substitute m = 4 and b = -3 into y = mx + b

Thus:

y = 4x - 3

Next, find the y-value of Function A when x = 2 by substituting x = 2 into y = 4x - 3

Thus:

y = 4(2) - 3

y = 8 - 3

y = 5

✅The y-value of Function A when x = 2 is 5

✔️Equation for Function B is given as,

y = ½x + 1

Find the y-value of Function B when x = 2 by substituting x = 2 into y = ½x + 1

Thus:

y = ½(2) + 1

y = 1 + 1

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✅The y-value of Function B when x = 2 is 2

Therefore, the correct statement is:

The y-value of Function A when x = 2 is greater than the y-value of Function B when x = 2

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3 years ago

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Note that
$log_{4} (x+3) = \frac{log_{2} (x+3)}{log_{2}4}$

Therefore, given
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$\frac{log_{2}(x+3)}{log_{2}4}=log_{2} (2x) \\ log_{2}(x+3) = log_{2}4 log_{2}(2x) \\ x+3 = (2x)^{log_{2}4}$
Because
log₂4 = log₂ 2² = 2 log₂ 2 = 2, therefore
x + 3 = (2x)² = 4x²
4x² - x - 3 = 0
This factorizes into
(4x + 3)(x - 1) = 0

Answer:
4x² - x - 3 = 0
or
4x + 3 = 0, and
x - 1 = 0

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