Question

The spectrum of a blackbody has a peak wavelength of 2.80×10-7 meters. What is its temperature, in kelvins?

Answer 1

Answer: $1.03\times 10^4K$

Explanation:

Using Weins displacement law:

$\lambda _{max}=\frac{b}{T}$

where $\lambda _{max}$ = wavelength  = $2.80\times 10^{-7}m$

b = constant =$2.897\times 10^{-3}mK$

T = Temperature in Kelvin = ?

Putting the values we get:

$2.80\times 10^{-7}m=\frac{2.897\times 10^{-3}mK}{T}$

$T=1.03\times 10^4K$

Thus the temperature of the blackbody will be $1.03\times 10^4K$