The angle of elevation is = 70° and the distance the airplane travelled in the air is = 17,557ft
<h3>Calculation of the distance travelled</h3>
- To calculate the angle of elevation of the airplane
tan x° = opposite/adjacent
where opposite = 16,500 feet
adjacent = 6,000 ft
tan x° = 16,500 / 6,000
tan x° = 2.75
X = arctan ( 2.75)
X = 70°
- To calculate the distance the airplane travelled in the air Pythagorean Theorem is used.
C² = a² + b²
C² = 16,500² + 6,000²
C² = 272250000 + 36000000
C² = 308250000
C= √308250000
C= 17,557ft
Learn more about Pythagorean Theorem here:
brainly.com/question/343682
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Hey there, again! :D
Since the angle measuring 38 degrees is adjacent to m<1, it will equal 180 degrees.
180-38= 142
m<1= 142 degrees
I hope this helps!
~kaikers
Answer:
B) 2 1/4
Step-by-step explanation:
Answer:
doubling the square Apex
Step-by-step explanation:
