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Bad White [126]
3 years ago
13

The value of x is ?

Mathematics
2 answers:
Lelechka [254]3 years ago
7 0

Answer:

None of the choices are correct.

Step-by-step explanation:

Considering this a right triangle, we may use the law of sines or "sohcahtoa" to find the length of x.

cos(45) = x/100\sqrt{2}

which equates to about x = 74.29174812021

tatuchka [14]3 years ago
6 0

Answer:

None of them because according to phythagorean thoerum

A^+b^=c^ I have checked it with that and didn't get the answer in the following options

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<span>7×(20÷(11-9))+2÷8
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Hope this helps. Could you name me the brainliest?
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1 dozen roses for $29.75 how much does one rose cost
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Step-by-step explanation:

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Determine whether a triangle can be formed with the given side lengths.
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4 years ago
A machine in the student lounge dispenses coffee. The average cup of coffee is supposed to contain 7.0 ounces. A random sample o
Elenna [48]

Answer:

t=\frac{7.4-7}{\frac{0.7}{\sqrt{7}}}=1.512    

The degrees of freedom are

df=n-1=7-1=6  

And the p value for this case is:

p_v =2*P(t_{(6)}>1.512)=0.181  

The p value is a higher value and using a significance levels of 5% or 10% we see that the p value is higher than the significance level and then we FAIL to reject the null hypothesis and we don't have enough evidence to conclude that the true mean is different from 7 ounces.

Step-by-step explanation:

Information provided

\bar X=7.4 represent the sample mean

s=0.7 represent the sample standard deviation

n=7 sample size  

\mu_o 7 represent the value to verify

t would represent the statistic

p_v represent the p value

System of hypothesis

We want to verify if the average amount of coffee per cup is different from 7 ounces, the system of hypothesis would be:  

Null hypothesis:\mu = 7  

Alternative hypothesis:\mu \neq 7  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{7.4-7}{\frac{0.7}{\sqrt{7}}}=1.512    

The degrees of freedom are

df=n-1=7-1=6  

And the p value for this case is:

p_v =2*P(t_{(6)}>1.512)=0.181  

The p value is a higher value and using a significance levels of 5% or 10% we see that the p value is higher than the significance level and then we FAIL to reject the null hypothesis and we don't have enough evidence to conclude that the true mean is different from 7 ounces.

7 0
3 years ago
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