Answer:
Rational
Step-by-step explanation:
<u>Rational numbers:</u>
Rational numbers are such numbers that can be expressed in the form p/q, where the value of q must not be equivalent to 0.
<u>Irrational numbers:</u>
These numbers cannot be expressed in the form p/q, where the value of q must not be equivalent to 0. <u> </u>
Thus, 2.89 is a rational number.
The answer is not infinity.
<span>Consider FBDs of each mass with the direction of motion of m1 as positive </span>
<span>m1*g-T=m1*a </span>
<span>T-m2*g=m2*a </span>
<span>assuming mass less cord and mass less, friction less pulley </span>
<span>the accelerations are equal </span>
<span>a=(T-m2*g)/m2 </span>
<span>m1*g-T=m1*(T-m2*g)/m2 </span>
<span>do some algebra </span>
<span>m1*g-T=m1*T/m2-m1*g </span>
<span>2*m1*g=T*(1+m1/m2) </span>
<span>2*m1*m2*g=T*(m2+m1) </span>
<span>2*m1*m2*g/(m2+m1)=T </span>
<span>now take the limit of T as m1->infinity </span>
<span>T=2*m2*g </span>
<span>this is intuitively correct since the maximum acceleration of m1 is -g, the cord transfers the acceleration to m2, which is being acted on by gravity downward and an upward acceleration of g. Therefore the maximum acceleration of m1 is 2*g upward. </span>
Answer:
Step-by-step explanation:
For a
2 + x = 15
x = 15 -2
x = 13
For B
x - 12 = 14
x = 12 + 14
x = 26
For C
3x = 12
x = 12/3
x = 4
Hope it helps:)
Answer:
12.56 yards
Step-by-step explanation:
circumference = π x diameter
4 x 3.14 = 12.56
A researcher used simple random sampling in collecting grade-point averages of statistics students. From there, he calculated the mean of the sample.
The question: “Under what conditions can the sample mean he got be treated as a value from a population having a normal distribution?” can be answered by the central limit theorem which states that: Given a population with a finite mean μ and a finite non-zero variance σ2, the sampling distribution of the mean N approaches a normal distribution. if sample size, increases. The researcher needs to increase the number of statistics students so the variance of the sampling distribution of the mean will become smaller.