4 years ago

Someone pls me out with this problem. Divide m2n2/p3 by mp/n2

Mathematics

1 answer:

wel4 years ago

4 0

Answer:

$\dfrac{mn^5}{p^4}$

Step-by-step explanation:

As with dividing any fractions, invert the denominator and multiply. Use the rules of exponents to combine factors.

$\dfrac{\dfrac{m^2n^3}{p^3}}{\dfrac{mp}{n^2}}=\dfrac{m^2n^3}{p^3}\cdot\dfrac{n^2}{mp}\\\\=\dfrac{m^2n^3n^2}{p^3mp}=\dfrac{m^{2-1}n^{3+2}}{p^{3+1}}=\dfrac{mn^5}{p^4}$

_____

The applicable rules are ...

$a^ba^c=a^{b+c}\\\\\dfrac{a^b}{a^c}=a^{b-c}$

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Answer:

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Step-by-step explanation:

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Therefore, the absolute minumun is

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The approximation to the integral is

$\frac{3}{5}(2-0)\leq \int\limits^2_0 {f(x)} \, dx \leq 3(2-0)$

hence

$\frac{3}{5}(2)\leq \int\limits^2_0 {f(x)} \, dx \leq 3(2)\\\frac{6}{5} \leq \int\limits^2_0 {f(x)} \, dx \leq 6\\1.2 \leq \int\limits^2_0 {f(x)} \, dx \leq 6$