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3 years ago

Using the given function below, determine if the following coordinate points area solution to the function

Mathematics

1 answer:

eduard3 years ago

8 0

Answer:

see explanation

Step-by-step explanation:

To determine if the points are a solution substitute the x- coordinate into the function and if the value obtained is equal to the y- coordinate of the point then it is a solution

(1, 5)

y = 3(1)² + 1 = 3 × 1 + 1 = 3 + 1 = 4 ≠ 5 ← (1, 5) is not a solution

(- 2, 13)

y = 3(- 2)² + 1 = 3 × 4 + 1 = 12 + 1 = 13 ⇒ (- 2, 13) is a solution

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Plz help this is also timed and sorry that the screen looks like this:(

Galina-37 [17]

Answer:

2 hours, 15 minutes

Step-by-step explanation:

3:30 to 5:30 is 2 hours elapsed time.

5:30 to 5:45 is 15 minutes elapsed time.

2 hrs + 15 mins =2 hrs 15 mins.

6 0

3 years ago

Read 2 more answers

HELP ME PLEASE!!

LUCKY_DIMON [66]

Using a system of equation, we have that:

x, which is the cost of on-site service.
y, which is the cost of at-store service.
z, which is the cost of by-mail service.

The system is:

$x = 3y$

$z = y - 10$

$15x + 40y + 5z = 3100$

The cost of one on-site repair service is of $90.

Item a:

The variables are:

x, which is the cost of on-site service.
y, which is the cost of at-store service.
z, which is the cost of by-mail service.

Item b:

On-site service costs 3 times as much as at-store service, thus:

$x = 3y$

By mail service costs $10 less than at-store service, thus:

$z = y - 10$

Last week, the shop completed 15 services on-site, 40 services at-store, and 5 services by mail for total sales of $3100, thus:

$15x + 40y + 5z = 3100$

The system is:

$x = 3y$

$z = y - 10$

$15x + 40y + 5z = 3100$

Item c:

The cost of one on-site repair service is x.
First, replacing the first two equations into the third, we find y, and then with it we find x.

$15x + 40y + 5z = 3100$

$15(4y) + 40y + 5(y - 10) = 3100$

$60y + 40y + 5y = 3150$

$105y = 3150$

$y = \frac{3150}{105}$

$y = 30$

Then

$x = 3y = 3(30) = 90$

The cost of one on-site repair service is of $90.

A similar problem is given at brainly.com/question/24823220

3 0

3 years ago

What fractions are greater than 7/12

Vsevolod [243]

Answer:

8/12 and higher. To ensure an accurate answer, are there other fractions to compare "7/12" to?

Step-by-step explanation:

8 0

2 years ago

A restaurant chain has two locations in a medium-sized town and, believing that it has oversaturated the market for its food, is

scoray [572]

Answer:

Yes, since the test statistic value is greater than the critical value.

Step-by-step explanation:

Data given and notation

$\bar X_{1}=360000$ represent the mean for the downtown restaurant

$\bar X_{2}=340000$ represent the mean for the freeway restaurant

$s_{1}=50000$ represent the sample standard deviation for downtown

$s_{2}=40000$ represent the sample standard deviation for the freeway

$n_{1}=36$ sample size for the downtown restaurant

$n_{2}=36$ sample size for the freeway restaurant

t would represent the statistic (variable of interest)

$\alpha=0.05$ significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the true mean of revenue for downtown is higher than for freeway restaurant, the system of hypothesis would be:

Null hypothesis: $\mu_{1}\leq \mu_{2}$

Alternative hypothesis: $\mu_{1} > \mu_{2}$

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Determine the critical value.

Based on the significance level $\alpha=0.05$ and $\alpha/2=0.025$ we can find the critical values from the t distribution dith degrees of freedom df=36+36-2=55+88-2=70, we are looking for values that accumulates 0.025 of the area on the right tail on the t distribution.

For this case the value is $t_{1-\alpha/2}=1.66$

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$t=\frac{360000-340000}{\sqrt{\frac{50000^2}{36}+\frac{40000^2}{36}}}}=1.874$

What is the p-value for this hypothesis test?

Since is a right tailed test the p value would be:

$p_v =P(t_{70}>1.874)=0.033$

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean for the downtown revenue restaurant seems higher than the true mean revenue for the freeway restaurant.