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3 years ago

True or False: The following pair of ratios forms a proportion.

Mathematics

2 answers:

REY [17]3 years ago

7 0

Answer:

False because for two fractions to be proportional they must be equivalent

Gre4nikov [31]3 years ago

4 0

False because one is a improper fraction

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What would it be , x-axis or y-axis ?? Anyone knows I’ll give you best brainliest please help me out

BaLLatris [955]

Answer:

I believe the answer is y-axis

Step-by-step explanation:

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3 years ago

The graph represents the approximate number of bacteria in a population over time. Is the rate of change constant or varying? Ho

alisha [4.7K]

Answer:

Varying

Step-by-step explanation:

The reason why the rate of change is varying is because the dots on the graph do not connect to make a straight line when you draw a line through the dots. When the dots connect via a straight line, it is also known as a proportional relation. A straight line would be a constant change.

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2 years ago

Jillian is using integer tiles to add 7 + (negative 2). She uses the steps below.Step 17 positive tiles.Step 27 positive tiles a

NemiM [27]

Answer:

Step-by-step explanation:

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2 years ago

In circle o, mZWBY = 72°.

likoan [24]

Answer:

Answer is B. 36 degrees

Step-by-step explanation:

From the diagram,

angle WBY = 2 × angle WXY

angle WBY = 72°

angle WXY =

$\frac{angle \: WBY}{2}$

$= \frac{72}{2}$

$= 36 \: degrees$

7 0

3 years ago

Plz show work and solve quick please need help!!!!!

Simora [160]

Surface area is just the area of all these 4 triangles plus the rectangle.

First we can find the area of the rectangle.

$\sf A=lw$

Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.

$\sf A=(56)(27)$

$\sf A=1512cm^2$

The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:

$\sf 82.8-28=54.8\? cm$

Calculate the area:

$\sf A=\dfrac{1}{2}bh$

$\sf A=\dfrac{1}{2}(27)(54.8)$

$\sf A=739.8\?cm^2$

We have two of these triangles.

$\sf 739.8\times 2=1479.6\? cm^2$

Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:

$\sf 81.2-27=54.2\?cm$

Now find the area:

$\sf A=\dfrac{1}{2}bh$

$\sf A=\dfrac{1}{2}(56)(54.2)$

$\sf A=1517.6\? cm^2$

We have two of these triangles.

$\sf 1517.6\times 2=3035.2\?cm^2$

Add all the areas together:

$\sf 1512+1479.6+3035.2=\boxed{\sf 6026.80\? cm^2}$

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4 years ago