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mr_godi [17]
3 years ago
9

Identify the class midpoints for the given frequency distribution.

Mathematics
1 answer:
german3 years ago
8 0

Answer:

s

Step-by-step explanation:

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The area of a trapezoid is 864cm². It has a height of 24 cm, and the length of one of its bases is 30 cm. What is the length of
Amiraneli [1.4K]

The area <em>A</em> of a trapezoid with height <em>h</em> and bases <em>b</em>₁ and <em>b</em>₂ is equal to the average of the bases times the height:

<em>A</em> = (<em>b</em>₁ + <em>b</em>₂) <em>h</em> / 2

We're given <em>A</em> = 864, <em>h</em> = 24, and one of the bases has length 30, so

864 = (<em>b</em>₁ + 30) 24 / 2

864 = (<em>b</em>₁ + 30) 12

864 = (<em>b</em>₁ + 30) 12

72 = <em>b</em>₁ + 30

<em>b</em>₁ = 42

5 0
3 years ago
I need help with this question​
Artyom0805 [142]

Answer:

Step-by-step explanation:

It's algebra really, basically make a system of equations.

1b+5j=t

3b+2j=2t

I'm gonna solve the first one for buckets so we have it in terms of jars.

b+5j=t

b=t-5j

Now I plug that into the other equation

3b+2j=2t

3(t-5j)+2j=2t

3t-15j+2j=2t

Now, since it wants how many jars are in one tub, I want to solve it so there's 1t on one side of the equation and all js on the other.  or it other words solve for t.

3t-15j+2j=2t

3t-13j = 2t

3t = 2t+13j

t = 13j

So it takes 13 jars to make one tub, or one jar is 1/13 of a tub.  You could then plug that in to one of the equations and find how much a  bucket is.  

5 0
3 years ago
Pls Help, this is due very soon. Everything is in the picture
Digiron [165]

Answer:

55.48° or round it to 55.50°

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
the areas of two similar rectangles are 338 cm squared and 73 cm squared. what is the similarity ratio of the perimeters
Elena L [17]
The similarity ratio is 338 : 73. 

You cannot simplify this ratio any further, since 73 is a prime number.
3 0
3 years ago
A. Lin is using the diagram to prove the statement, "If a parallelogram has one
BigorU [14]

The congruence of the angles and triangles are proven as follows;

a. The composition angles of FGH are alternate interior angles to the composition angles of angle AHEF

b. The three sides of triangle ∆EHG are congruent to the three sides of triangle ∆GFE, therefore, triangles ∆EHG and ∆GFE are congruent by SSS congruency rule

<h3>What are congruent triangles?</h3>

The lengths of the three sides of triangles that are congruent.

a. The shape of quadrilateral EFGH = A parallelogram

The measure of angle HEF = 90°

Angle HEF = 90°

Angle HEF = Angle HED + Angle DEF

Angle HED is congruent to angle FGD (Alternate interior angles theorem)

Angle HED = angle FGD

Angle DEF is congruent to angle DGH (Alternate interior angles theorem)

Angle DEF = angle DGH

Angle FGH = Angle FGD + Angle DGH

Angle FGH = Angle HED + Angle DEF (Substitution property)

Angle FGH = Angle HEF (Transitive property)

Angle FGH = Angle HEF = 90°

Therefore, the statement that will help prove angle FGH is also a right is that angle FGH is the sum of angles FGD and angle DGH which are alternate interior angles to angles HED and DEF which makes up angle HEF, which is a right angle.

b. The two-column method can be used to prove that triangle EHG and triangle GFE are congruent as follows;

Statement. Reason

EF is congruent to HG. Opposite sides of a parallelogram are congruent

EH is congruent FG Opposite sides of a parallelogram are congruent

EG is congruent to EG Reflexive property of congruency

∆EHG is cong. to ∆GFE SSS, Side-Side-Side, congruency rule

Learn more about the triangle congruency rules here:

brainly.com/question/15338506

#SPJ1

4 0
9 months ago
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