$4x^2-35x+4\\\\a=4;\ b=-35;\ c=4\\\\\Delta=b^2-4ac\to\Delta=(-35)^2-4\cdot4\cdot4=1225-64=1161\\\\x=\frac{-b\pm\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{1161}=\sqrt{9\cdot129}=3\sqrt{129}\\\\x=\frac{-(-35)\pm3\sqrt{129}}{2\cdot4}=\frac{35\pm3\sqrt{129}}{8}\\\\4x^2-35x+4=4\left(x-\frac{35-3\sqrt{129}}{8}\right)\left(x-\frac{35+3\sqrt{129}}{8}\right)$

8 0

2 years ago

Say if you had a Right triangle with sides being 12a 15b and the last side unkown how would i solve it?

balandron [24]

By Pythagorean theorem,
a^2+b^2=c^2
c is the longest side of the triangle
a and b are the remaining sides

5 0

2 years ago

A corporate team building event costs $2 for every attendee. If there are 8 attendees how much will the corporate team building

lesantik [10]

Answer:

16$

Step-by-step explanation:

8 times 2 is 16

I hope this helps!!!

7 0

3 years ago

Yo help me out please.

katrin2010 [14]

Answer:

Step-by-step explanation:

-12 = -3/4x + 3

-9 = -3/4x

-9 = (-3/4) times x

-9 = (-3/4) times 12

hope this helps! :)

6 0

3 years ago