1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
True [87]
3 years ago
11

BRAINLIESTT ASAP! PLEASE HELP ME :) thanks!!

Mathematics
1 answer:
Paraphin [41]3 years ago
4 0

Answer:

third option

Step-by-step explanation:

<u>angle 1</u>

measure of angle 1 is diagonal to 45, theyre congruent angles

so measure of angle 1 is 45

<u>angle 2</u>

the sum of a triangle is 180 degrees

so for measure 2, we add 45 + 59 and we get 104. then we do 180 - 104 and we get 76

so the measure of angle 2 is 76

<u>angle 3</u>

since we know that the measure for angle 1 is 45, we can also solve for the measure of angle 3

to find angle 3, we do 55 + 45 and we get 100

and then you do 180 - 100 and you get 80

so the measure of angle 3 is 80

You might be interested in
4. What percent of 20 is 5?​
Sladkaya [172]

Answer:

25%

Step-by-step explanation:

5 x 4 = 20 and 4 x 25% is 100%

7 0
3 years ago
Find the product and list the unit rates
lisabon 2012 [21]
Answer: 3/19 107% 216%
3 0
2 years ago
Read 2 more answers
Suppose the diameter of a circle is 6 units What is its circumference?
Kipish [7]

Answer:

18.84 estimated, 6π exactly

Step-by-step explanation:

Hi!

<u>The formula for finding the circumference of a circle is 2πr:</u>

In that case, all we need to do <em>first </em>is to divide the diameter by 2, so we can substitute that into the equation.

6 ÷ 2 = 3

So we have 2π × 3 to solve.

2π × 3 = 6π

We can estimate the circumference by multiplying by 3.14.

6 × 3.14 = 18.84

(actually multiplying by π gives 18.849... which is pretty close!)

Thus, the circumference is \boxed{6\pi{\text{\:or\:18.84\:roughly}}}.

Hope this helps!

6 0
3 years ago
Express your answer exactly
nekit [7.7K]

Answer:

I would love to help you but were just getting into  this subject

Step-by-step explanation:

6 0
3 years ago
Of the 58 employees in a firm, 8 are considered support staff, and 7 of the employees have more than five years of experience. A
polet [3.4K]

Using statistical concepts, it is found that the number of outcomes that are possible for the complement of the union of Events J and K is of 43.

<h3>What is the union of events J and K?</h3>

It means that at least one of event J or event K is true, hence, it is composed by employees that are either considered support staff(less than 5 years of experience) or employees that have more than five years of experience, combining a total of 7 + 8 = 15 employees.

<h3>What is the complement?</h3>

The total number of outcomes of the union of J and K, plus the complement, add to the total number of 58, hence:

15 + x = 58

x = 43.

The number of outcomes that are possible for the complement of the union of Events J and K is of 43.

More can be learned about complementary events at brainly.com/question/9752956

6 0
2 years ago
Other questions:
  • A dollar bill is about 0.00011 meter thick. What is this thickness is scientific notation?
    5·1 answer
  • What's the awnser to this
    10·2 answers
  • Is the function f even odd or neither​
    15·1 answer
  • Show 2 ways three people can share a 5-segment chewy fruit worm<br><br> can u help me plz:)
    13·1 answer
  • .You deposit $200 in an account earning 3.5% simple interest. How long will it take for the
    12·1 answer
  • Convert the following repeating decimal to fractions 0.123232323...
    12·1 answer
  • Change x-2y=4 into slope-intercept form.
    7·1 answer
  • 12) Kyle bought onions at $0.96 per pound. He paid $4.32<br> total. How many pounds did he buy?
    10·1 answer
  • I need help on this ixl question
    6·1 answer
  • Determine whether each figure creates the conditions to form a unique triangle, more than one triangle, or no triangle. Angle me
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!