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2 years ago

14

Which of the following represents the difference between the central angles of the above regular polygons? Round to the nearest

hundredth.

1 answer:

solong [7]2 years ago

6 0

Answer:

its 15.43

Step-by-step explanation:

you didnt put a picture for the polygons but im pretty sure this is from math nation.

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A pipe consists of two concentric cylinders, with the inner cylinder hollowed out. Describe how you could calculate the volume o

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Answer:

cylinder formula

Step-by-step explanation:

4 0

3 years ago

seropon [69]

Answer:

Que estas como por que nada

Step-by-step explanation:

buenos nochas

3 0

3 years ago

Root 8 + 3 root 32 - root 50

lisov135 [29]

$\sqrt{8} + 3 \sqrt{32} - \sqrt{50}$

$= \sqrt{4 \times 2} + 3 \sqrt{16 \times 2} - \sqrt{25 \times 2}$

$= 2\sqrt{ 2} + 12 \sqrt{2} - 5\sqrt{ 2}$

$= 9\sqrt{ 2}$

6 0

3 years ago

The radius of a cone is increasing at a constant rate of 7 meters per minute, and the volume is decreasing at a rate of 236 cubi

storchak [24]

Answer:

The rate of change of the height is 0.021 meters per minute

Step-by-step explanation:

From the formula

$V = \frac{1}{3}\pi r^{2}h$

Differentiate the equation with respect to time t, such that

$\frac{d}{dt} (V) = \frac{d}{dt} (\frac{1}{3}\pi r^{2}h)$

$\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (r^{2}h)$

To differentiate the product,

Let r² = u, so that

$\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (uh)$

Then, using product rule

$\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h\frac{du}{dt}]$

Since $u = r^{2}$

Then, $\frac{du}{dr} = 2r$

Using the Chain's rule

$\frac{du}{dt} = \frac{du}{dr} \times \frac{dr}{dt}$

∴ $\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h(\frac{du}{dr} \times \frac{dr}{dt})]$

Then,

$\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]$

Now,

From the question

$\frac{dr}{dt} = 7 m/min$

$\frac{dV}{dt} = 236 m^{3}/min$

At the instant when $r = 99 m$

and $V = 180 m^{3}$

We will determine the value of h, using

$V = \frac{1}{3}\pi r^{2}h$

$180 = \frac{1}{3}\pi (99)^{2}h$

$180 \times 3 = 9801\pi h$

$h =\frac{540}{9801\pi }$

$h =\frac{20}{363\pi }$

Now, Putting the parameters into the equation

$\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]$

$236 = \frac{1}{3}\pi [(99)^{2} \frac{dh}{dt} + (\frac{20}{363\pi }) (2(99)) (7)]$

$236 \times 3 = \pi [9801 \frac{dh}{dt} + (\frac{20}{363\pi }) 1386]$

$708 = 9801\pi \frac{dh}{dt} + \frac{27720}{363}$

$708 = 30790.75 \frac{dh}{dt} + 76.36$

$708 - 76.36 = 30790.75\frac{dh}{dt}$

$631.64 = 30790.75\frac{dh}{dt}$

$\frac{dh}{dt}= \frac{631.64}{30790.75}$

$\frac{dh}{dt} = 0.021 m/min$

Hence, the rate of change of the height is 0.021 meters per minute.

3 0

3 years ago

Please help if you can!!!!

storchak [24]

Answer:Well, I don't know what you got so I can't tell you if it is right.

If it works in both equations, it depends of whether your equations are set up correctly.

Here is how I would do this problem.

Let x = no. of hot dogs,y = number of sodas.

First equation is just about the number of things.

x + y = 15

Second equation is about the cost of things.

1.5 x + .75 y = 18

solve x+y = 15 for y y = 15-x substitute into second equation

1.5x + .75(15 - x) = 18

You should get the correct answer for number of hot dogs if you solve this correctly. Put your answer in the x + y =15 equation to get y. Then put both x and y into the cost equation and check your answer.

Hope this helps.

Step-by-step explanation:

5 0

3 years ago