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Vlada [557]
3 years ago
5

The difference of the squares of two positive consecutive even integers is 68 find the integers use the fact that if X represent

s an even integer then X +2 represents the next consecutive even integers
Mathematics
2 answers:
Burka [1]3 years ago
5 0

Answer:

16 and 18

Step-by-step explanation:

Here, x represents the even integer then the even consecutive next integer is x + 2,

According to the question,

(x+2)^2-x^2=68

x^2+4x+4-x^2=68  ( Using (a+b)² = a² + 2ab + b² )

4x+4=68                 ( Combining the like terms )

4x=64

\implies x = \frac{64}{4}=16

Hence, first integer = 16,

Second integer = 16 + 2 = 18.

Verdich [7]3 years ago
4 0
The two positive consecutive integers we'll call x and x+2. then (x+2)² - x² =68
x²+4x+4-x²=68
4x=64
x=16

the integers are 16 and 18
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brainly.com/question/196661

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