1.) The sum(addition) of 21 and 5 times(multiplication) a number f is(=) 61.
f = unknown number/variable [So 21 plus 5f(5 times f) equals 61]
21 + 5f = 61 [21(one-time) + 5f(number x variable) = 61(total)]
2.) Seventeen more(addition) than seven times(multiplication) a number j is(=) 87.
j = unknown number/variable [So 17 plus 7j(7 times j) equals 87]
17 + 7j = 87
3.) n = number of calls
18 + 0.05n = 50.50
[Company charges $18 plus five cents per call(n), and the total charge was $50.50]
4.) s = the number of students
40 + 30s = 220
[Tutor charges $40 plus $30 per student(s), and the total charge was $220]
For solving this we need the change in distance and the change in time. You said that the change in time is 1.8 seconds and the change in distance is 3.6 meters. ( This is assuming it started at 0 meters and started at 0 seconds )
Since the starting was 0,0 we can toss them out as they add no value. Now since speed is labeled (in this case) m/s, we divide how many meters it traveled over how many seconds it took to travel it.
3.6 / 1.8 = 2
The average speed of the cart is 2 m/s
Answer:
A(t) = 90e^0.12t ;
299 mg
Step-by-step explanation:
General Continous growth rate equation :
A = Pe^rt
A = amount present, t years after year of initial amount.
Here,
P = 90 mg, amount in year 2000
r = rate = 12% = 0.12
t = years after 2000
Therefore,
A is written as ;
A(t) = 90e^0.12t
Amount present in year 2010 ;
t = 2010 - 2000 = 10
A(10) = 90e^0.12(10)
A(10) = 90 * e^1.2
= 90 * 3.3201169
= 298.81052
= 299 mg
Answer:
ima guess $262.50
Step-by-step explanation:
So,
"six feet less than"
- 6
"the width"
w
w - 6
"six feet less than the width (w)"
w - 6
