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Artyom0805 [142]
3 years ago
9

Which of the following is true of the data set represented by the box plot?

Mathematics
2 answers:
Assoli18 [71]3 years ago
8 0

Answer:

<h2>Removing the outliers would not affect the median.</h2>

Step-by-step explanation:

The outliers represent those values that lie outside, that is, they are much smaller or much larger than the rest of the values.

So, in this case, outliers refer to the least and greatest value, if we remove them, the median would be the same, because they median is the center of all values, so, if we eliminate the least and the greatest at the same time, the center would remain the same.

The only way to affect the median is by eliminating the least or the greatest value, if we eliminate just one of them, the median would be affected.

Therefore, the right answer is the last choice.

Nuetrik [128]3 years ago
5 0

Answer:

Removing the 16 and 86 would not effect the median.

Step-by-step explanation:

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Suppose the probability of passing a driving test is 65%. (a) on a certain afternoon 15 people are tested. (i) what is the expec
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In this current scenario,
Probability of passing, p = 65% = 0.65
Then,
Probability of not passing, q = 1-p = 1-0.65 = 0.35

Part (a): When 15 people are tested
(i) Number of people expected to pass
This is 65% of the 15 people tested. That is,
Number of people expected to pass = 0.65*15 = 9.75. This is rounded downwards as upward rounding will violate the 65% criteria.
Therefore,
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(ii) Probability that 11 people are expected to pass the test
p(x=11) = [15Cx]*p^x*q^(15-x) = [15C11]*0.65^11*0.35^(15-11) = 0.1792 ≈ 17.92%

Part (b): Teenager determined to pass the test no matter how many times

(i) Probability that he passes the test the third time
This means that he will fail the first and second time. That is,
Probability pf passing the third time = q*q*p = 0.35*0.35*0.65 = 0.079625 = 7.9625%

(ii) Number of trials it takes to pass
This is a case of mathematical expected, E, that it takes before first occurrence of success. Normally,
E = 1/p
Substituting;
E = 1/0.65 = 1.54 ≈ 2
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Answer:

Step-by-step explanation:

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Hope this helps!

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