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AysviL [449]
4 years ago
15

SAT Scores Suppose that the mathematics SAT scores for high school seniors for a specific year have a mean of 456 and a standard

deviation of 100 and are approximately normally distributed. If a subgroup of these high school seniors, those who are in the National Honor Society, is selected, would you expect the distribution of scores to have the same mean and standard deviation? Explain your answer.
Mathematics
1 answer:
maxonik [38]4 years ago
7 0

Answer:

The distribution of scores would not have the same mean and standard deviation

Step-by-step explanation:

According to the given data we have the following:

mean=456

Standard deviation=100

mathematics SAT scores for high school seniors for a specific year have a mean of 456 and a standard deviation of 100 and are approximately normally distributed

Therefore, we can conclude that a subgroup of these high school seniors would not to be a perfect representation, hence, the distribution of scores would not have the same mean and standard deviation.

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The spinner is divided into 12 equal sectors. What is the possibility of not spinning a 2?
scZoUnD [109]

Answer:

11/12

Step-by-step explanation:

I am assuming the spinner is divided into 12 equal sectors and numbers 1-12 are written on them. Comment if I am wrong.

Spinning the 12 sided spinner, there is a 1/12 chance of spinning a specific number. So we take the opposite of that, which is 11/12. The chances of not rolling a two mean it comes out true if you roll numbers 1, 3, 4, 5, 6, 7, 8, 9, 10, 11, and 12.

3 0
3 years ago
In a random sample of 90 students in first grade, the mean hours of sleep per night was 9.2 with a standard deviation of 0.37 in
ss7ja [257]

Answer:

Option C is right

Step-by-step explanation:

Given are two samples

I group has sample size 90, mean = 9.2 and std dev =0,.37

II group has sample size 70, mean = 7.3 and std dev = 0.58

we find that mean difference i.e. difference between mean hours of sleep between two groups

= 9.2-7.3 = 1.9

Std error for difference = 0.0620

Since sample size is sufficiently large we can use Z critical for 99%

i.e. 2.58

Margin of error =±2.58(0.062)

=0.16

Hence confidence interval 99% for difference in hours of sleep

= (1.9-0.16,1.9+0.16)

=(1.74, 2.06)


5 0
4 years ago
I wasn't at school when they were teaching theoretical and experimental experimental. can someone explain how it works and give
Alexandra [31]
Hey I am just like u I wasn't at school I have been waiting for 1 hour and Noone had answer me I am sad I am going to fail
5 0
4 years ago
Solve for x: 3x^2+6x=2
vekshin1

Answer:

x = -1±sqrt(5/3)

Step-by-step explanation:

3x^2+6x=2

We will use completing the square

Factor out a 3 on the left

3(x^2 +2x) = 2

Divide each side by 3

3/3(x^2 +2x) = 2/3

(x^2 +2x) = 2/3

2/2 = 1 1^2 =1

Add 1 to each side

(x^2 +2x+1) = 2/3+1

(x+1) ^2 = 2/3 +3/3

(x+1)^2 = 5/3

Take the square root of each side

sqrt((x+1)^2) = ±sqrt(5/3)

x+1 = ±sqrt(5/3)

Subtract 1 from each side

x+1-1 = -1±sqrt(5/3)

x = -1±sqrt(5/3)


7 0
3 years ago
Read 2 more answers
If 6 pens cost $2.40 What is the cost of 9 pens?
Shkiper50 [21]

Answer:

3.60$

Step-by-step explanation:

if we bought 3 pens that would equal 1.20$ so we add 1.20$ to 2.40$ we get 3.60$

3 0
3 years ago
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