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3 years ago

What dose a and x equal 2³x 5- (√-1) a+ 5a - 3÷ x³

Mathematics

1 answer:

ser-zykov [4K]3 years ago

7 0

The terms in which value of x when substituted leaves final value of p(x) = "0".

Here, x - 2 is factor. So value of x is 2.

Substituting value of x we get,

p(x) = x3 - 3x + 5a

p(2) = 2*3 - 3(2) + 5a

0+ 8-6 + 5a

-2 = 5a

a= -0.4

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Divide 80 in a ratio of 3:2

soldi70 [24.7K]

Answer:

Let the number be x

Ratio states that as the comparison of sizes of two quantities of the same unit.

Given : Ratio 3:2

The first number be 3x and

the second number be 2x.

then,

As per the condition:

$3x+2x=80$

Combine like terms;

5x = 80

Divide both sides by 5 , to solve for x;

$\frac{5x}{5}= \frac{80}{5}$

Simplify:

x=16

Then, the numbers are:

$3x =3 \times 16 = 48$ and

$2x =2 \times 16 = 32$ .

Therefore, the number 80 is divided in the ratio of 3:2 is, 48 and 32.

6 0

4 years ago

Read 2 more answers

Jill has a collection of bugs. Her collection contains butterflies and tarantulas. She has 47 bugs and counts 320 total legs. (N

prisoha [69]

Answer:

The solution to this system of equations is:

B = 28
T = 19

Step-by-step explanation:

We are given that Jill has 47 bugs and counts a total 320 legs.

We can concur that by adding the total number of butterflies and the total number of tarantulas, we will get 47 bugs.

$\text{tarantulas + butterflies} = 47$

We are also told that T is tarantulas and B is butterflies.

$T + B = 47$

Then, we also know that butterflies have 6 legs and tarantulas have 8 legs. So, for every tarantula, we get a multiple of 8 and for butterflies, we get a multiple of 6. This gives us a new equation:

$6B + 8T = 320$

Now, we can set up a system of equation.

$\displaystyle \left \{ {{B + T = 47} \atop {6B + 8T = 320}} \right.$

Using the first equation, we can solve for B.

$\displaystyle B + T = 47\\\\B + T - T = 47 - T\\\\B = 47 - T$

Then, we can substitute this value of B into the second equation and solve for T.

$\displaystyle 6(47-T)+8T=320\\\\282 - 6T + 8T = 320\\\\282 + 2T = 320\\\\2T + 282 = 320\\\\2T + 282 - 282 = 320 -282\\\\2T = 38\\\\\frac{2T}{2}=\frac{38}{2}\\\\T = 19$