Hmmm, as I read it, in year 1, but it doesn't say at the beginning of the year or end, so we'll be assuming is at the beginning of year 1, the amount is 850, how much will it be at the beginning of year 6? namely, 5 years later.
![\bf ~~~~~~ \textit{Simple Interest Earned Amount}\\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to& \$850\\ r=rate\to 8\%\to \frac{8}{100}\to &0.08\\ t=years\to &5 \end{cases} \\\\\\ A=850[1+0.08(5)]\implies A=850(1.4)](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%5C%5C%5C%5C%0AA%3DP%281%2Brt%29%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%0AP%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cto%26%20%5C%24850%5C%5C%0Ar%3Drate%5Cto%208%5C%25%5Cto%20%5Cfrac%7B8%7D%7B100%7D%5Cto%20%260.08%5C%5C%0At%3Dyears%5Cto%20%265%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D850%5B1%2B0.08%285%29%5D%5Cimplies%20A%3D850%281.4%29)
Find the sum of 5x+20 and the opposite of 20. Write an equivalent expression in standard form.
1 answer:
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Answer:
π =14 cm
Step-by-step explanation:
Given:
circumference of a circle =616 cm
pie(π)=22/7
circumference of a circle=πr^2
616=22/7 *r^2
616*7/22 =r^2
4312/22 =r^2
196=r^2
=r
14 =r