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Assoli18 [71]
3 years ago
11

Create a table-valued function named fnDateRange, similar to the stored procedure of exercise 3. The function requires two param

eters of data type smalldatetime. Don't validate the parameters. Return a result set that includes the InvoiceNumber, InvoiceDate, InvoiceTotal, and Balance for each invoice for which the InvoiceDate is within the date range. Invoke the function from within a SELECT statement to return those invoices with InvoiceDate between December 10 and December 20, 2011.

Computers and Technology
1 answer:
BabaBlast [244]3 years ago
5 0

Answer:

Please see the attached picture for the complete answer.

Explanation:

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5.23 LAB: Contains the character
torisob [31]

Answer:

In C++:

#include<iostream>

#include<vector>

using namespace std;

int main() {

int len;

cout<<"Length: ";  cin>>len;

string inpt;

vector<string> vect;

for(int i =0;i<len;i++){

  cin>>inpt;

  vect.push_back(inpt); }

char ch;

cout<<"Input char: ";  cin>>ch;  

for(int i =0;i<len;i++){

  size_t found = vect.at(i).find(ch);  

      if (found != string::npos){

          cout<<vect.at(i)<<" ";

          i++;

      }

}  

return 0;

}

Explanation:

This declares the length of vector as integer

int len;

This prompts the user for length

cout<<"Length: ";  cin>>len;

This declares input as string

string inpt;

This declares string vector

vector<string> vect;

The following iteration gets input into the vector

for(int i =0;i<len;i++){

  cin>>inpt;

  vect.push_back(inpt); }

This declares ch as character

char ch;

This prompts the user for character

cout<<"Input char: ";  cin>>ch;  

The following iterates through the vector

for(int i =0;i<len;i++){

This checks if vector element contains the character

  size_t found = vect.at(i).find(ch);  

If found:

      if (found != string::npos){

Print out the vector element

          cout<<vect.at(i)<<" ";

And move to the next vector element

          i++;

      }

}  

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Answer:

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Explanation:

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Answer:

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