Question

One cylinder has a volume that is 8 Centimeters cubed less than StartFraction 7 over 8 EndFraction of the volume of a second cylinder. If the first cylinder’s volume is 216 Centimeters cubed, what is the correct equation and value of x, the volume of the second cylinder?

Answer 1

The correct equation is:

$216 = \frac{7}{8} \times x - 8$

The volume of second cylinder is 256 centimeter cubed

Solution:

Given that,

One cylinder has a volume that is 8cm less than 7/8 of the volume of a second cylinder

The first cylinder’s volume is 216 centimeter cubed

From given,

Let "x" be the volume of second cylinder

Therefore,

Volume of first cylinder = 7/8 of the volume of a second cylinder - 8

$216 = \frac{7}{8} \times x - 8$

$216 = \frac{7x}{8}-8\\\\216 = \frac{7x-64}{8}\\\\7x - 64 = 8 \times 216\\\\7x - 64 = 1728\\\\7x = 1728 + 64\\\\7x = 1792\\\\Divide\ both\ sides\ by\ 7\\\\x = 256$

Thus the volume of second cylinder is 256 centimeter cubed

Answer 2

Answer:

7/8X-8=216       x=256

Step-by-step explanation:

7/8x-8=216

      +8  +8

7/8x=224

7/8    7/8

x=256