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3 years ago

I need help with b. please

Mathematics

1 answer:

aniked [119]3 years ago

8 0

Its 1/5,

35/100 - 15/100 = 20/100

for 20, 40, 60, 80, 100
1, 2, 3, 4, 5

so 20/100 = 1/5

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Please do not claim this unless you answer the question.

anygoal [31]

Negative , you always put the biggest numbers value at the end

7 0

1 year ago

Read 2 more answers

What is the solution of log3x − 5 16 = 2?

Stolb23 [73]

Answer:

log (16)=2 in base 3x-5

==>16=2^(3x-5)

==>2^4=2^(3x-5)

==>4=3x-5

==>3x=9

==>x=3

Step-by-step explanation:

4 0

2 years ago

a positive integer is twice another. The sum of the reciprocals of the two positive integers is frac 3/16, find the two integers

gizmo_the_mogwai [7]

Step-by-step explanation:

Let $x$ be the smallest integer

Let $2x$ be the larger integer

As the sum of the reciprocals of the two positive integers is frac 3/16

So,

$\frac{1}{x}\:+\:\frac{1}{2x}\:=\:\frac{3}{16}$

$\mathrm{Multiply\:by\:LCM=}16x$

$\frac{1}{x}\cdot \:16x+\frac{1}{2x}\cdot \:16x=\frac{3}{16}\cdot \:16x$

Simplify

$24=3x$

$\mathrm{Switch\:sides}$

$3x=24$

$\mathrm{Divide\:both\:sides\:by\:}3$

$\frac{3x}{3}=\frac{24}{3}$

$x=8$

So,

$2x=16$

<h2>Verification:</h2>

$\frac{1}{8}\:+\:\frac{1}{16}$

$\mathrm{Least\:Common\:Multiplier\:of\:}8,\:16:\quad 16$

$=\frac{2}{16}+\frac{1}{16}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{2+1}{16}$

$=\frac{3}{16}$

Therefore,

$\frac{1}{8}+\frac{1}{16}=\frac{3}{16}$

Keywords: word problem , integer

Learn more about solving integer word problem from brainly.com/question/10905225

#learnwithBrainly

4 0

3 years ago

Solve the inequality <br> -5(3m-2)>30

Ne4ueva [31]

Answer:

m < −4/3

Step-by-step explanation:

−5(3m−2)>30

Simplify both sides of the inequality.

−15m+10>30

Subtract 10 from both sides.

−15m+10−10>30−10

−15m>20

Divide both sides by -15.

−15m/−15 > 20/−15

m<−4/3

4 0

3 years ago

Read 2 more answers

Given any triangle in the plane, associate to each side an outward pointing normal vector of the same length as the side. Show t

Zigmanuir [339]

Let , a, b and c be the length of three sides of triangle, represented in terms of vectors as $\vec{a},\vec{b},\vec{c}$ .

Now, vector of same Magnitude acts as normal vector to each side.

So, equation of any vector p having normal q is given by

$\vec{p} \times\vec{q}$

Now sum of three vector and it's normal is given as

$=\vec{a} \times\vec{a}+\vec{b} \times\vec{b}+\vec{c} \times\vec{c}\\\\=0+0+0\\\\=0$

Cross product of two identical vectors is Zero.

$\rightarrow \vec{i} \times\vec{i}=0$

8 0

2 years ago