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Svetach [21]
3 years ago
9

The vertices of a quadrilateral in the coordinate plane are known. How can the perimeter of the figure be found?

Mathematics
2 answers:
bonufazy [111]3 years ago
7 0
Use the distance formula to find the length of each side, and then add the lengths.
iren2701 [21]3 years ago
6 0

Answer:

a

Step-by-step explanation:


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-10n + 24 + 30n = -36<br> Solve this equation
vladimir1956 [14]

Step-by-step explanation:

- 10n + 24 + 30n =  - 36

Collect like terms and simplify

[tex] -10n+30n=-36-24 \\ 20n = -60 [/tex]

Divide both sides of the equation by 20

[tex] 20n/20 = -60/20 \\ n=-3 [/tex]

8 0
3 years ago
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Which are acute, obtuse, or right?
qaws [65]
5,7 and 8 are right angles, and 6 is an acute angle this is because of u look at 9 and 10 you can see a little box looking thing under the h and if u do that to all of them 5, 7 and 8 can fit the little box but 6 you can’t because it is an acute angle. Hope this helped!
8 0
3 years ago
Yall are doing great thanks sm for the help
blondinia [14]

Answer:

That is an obtuse isosceles

4 0
3 years ago
Is 24+8 sometimes equivalent to 4 (6+2x)
velikii [3]
If ya distribute it it comes together as 24 + 8x soo i hope this helped
5 0
3 years ago
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WORTH 100 POINTS!
zzz [600]

Answer:

7miles

equations shown in work image below

work shown on the paper with more explanations because text is hard to write equations (sorry I used km but it is miles for your problem.)

:) please give a heart for thanks

and brainliest crown :)

Step-by-step explanation:

For both d=r*t

Each bikes to others house and leave at the same time so for Tony,

11 = 30*t

t= 11/30 hours

for Gerry,

11 = 25*t

t= 11/25 hours

Comparing these, with LCD,

Tony's time is 55/150

Gerry's time is 66/150

So Tony got to Gerry's house 11/150 hours quicker than Gerry got to Tony's house.

Now they turn around and head back toward each other. If they leave at the same exact time, the elapsed time for each until they met would be the same so t (for tony) = t (for gerry), but Tony got a head start.

We start the stopwatch when Gerry turns around 11/150 hours after Tony has turned around. If Gerry's time to where they meet from Tony's house t(gerry), then Tony's time from Gerry's house is t(gerry) + 11/150

5 0
3 years ago
Read 2 more answers
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