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Svetach [21]
3 years ago
9

The vertices of a quadrilateral in the coordinate plane are known. How can the perimeter of the figure be found?

Mathematics
2 answers:
bonufazy [111]3 years ago
7 0
Use the distance formula to find the length of each side, and then add the lengths.
iren2701 [21]3 years ago
6 0

Answer:

a

Step-by-step explanation:


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A playground has the shape of a trapezoid.
Dmitrij [34]

Answer:

  • short base: 6 yards
  • long base: 8 yards

Step-by-step explanation:

Our understanding of your figure is shown below.

The question says the "shortest side" and the "width" have the same dimension. If the "width" is a reference to "height 6 yards", then it seems the "shortest side" is 6 yards. Since the slant sides are longer than the height, the "shortest side" is also the "short base."

The short base is 6 yards.

__

The long base overhangs the short base by 1 yard on either end, so it is a total of 2 yards longer than the short base. It it 6+2 = 8 yards long.

The long base is 8 yards.

6 0
3 years ago
The graph of f ′ (x), the derivative of f(x), is continuous for all x and consists of five line segments as shown below. Given f
Nataliya [291]

The maxima of f(x) occur at its critical points, where f '(x) is zero or undefined. We're given f '(x) is continuous, so we only care about the first case. Looking at the plot, we see that f '(x) = 0 when x = -4, x = 0, and x = 5.

Notice that f '(x) ≥ 0 for all x in the interval [0, 5]. This means f(x) is strictly increasing, and so the absolute maximum of f(x) over [0, 5] occurs at x = 5.

By the fundamental theorem of calculus,

\displaystyle f(5) = f(0) + \int_0^5 f'(x) \, dx

The definite integral corresponds to the area of a trapezoid with height 2 and "bases" of length 5 and 2, so

\displaystyle \int_0^5 f'(x) \, dx = \frac{5+2}2 \times 2 = 7

\implies \max\{f(x) \mid 0\le x \le5\} = f(5) = f(0) + 7 = \boxed{13}

8 0
2 years ago
Find the standard deviation of 21, 31, 26, 24, 28, 26
Vesnalui [34]

Given the dataset

x = \{21,\ 31,\ 26,\ 24,\ 28,\ 26\}

We start by computing the average:

\overline{x} = \dfrac{21+31+26+24+28+26}{6}=\dfrac{156}{6}=26

We compute the difference bewteen each element and the average:

x-\overline{x} = \{-6,\ 5,\ 0,\ -2,\ 2,\ 0\}

We square those differences:

(x-\overline{x})^2 = \{36,\ 25,\ 0,\ 4,\ 4,\ 0\}

And take the average of those squared differences: we sum them

\displaystyle \sum_{i=1}^n (x-\overline{x})^2=36+25+4+4+0+0=69

And we divide by the number of elements:

\displaystyle \sigma^2=\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n} = \dfrac{69}{6} = 11.5

Finally, we take the square root of this quantity and we have the standard deviation:

\displaystyle\sigma = \sqrt{\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n}} = \sqrt{11.5}\approx 3.39

8 0
3 years ago
Each point on the edge of a circle is equidistant from the center of the circle. The center of a circle is located at (6, 3). Wh
vladimir2022 [97]

Answer:

yes its A

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find one value of x that is a solution to the equation:<br> (3x + 7)2 = -6x – 14
lara [203]

Answer: x = -7/3

Step-by-step explanation:

https://www.symbolab.com/solver/step-by-step/%5Cleft(3x%20%2B%207%5Cright)2%20%3D%20-6x%20-%2014

there are the steps

8 0
3 years ago
Read 2 more answers
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