let's recall that a cube is just a rectangular prism with all equal sides, check picture below.
![\bf \textit{volume of a cube}\\\\ V=s^3~~ \begin{cases} s=&length~of\\ &a~side\\ \cline{1-2} V=&27000 \end{cases}\implies 27000=s^3\implies \sqrt[3]{27000}=s\implies 30=s \\\\[-0.35em] ~\dotfill\\\\ \textit{surface area of a cube}\\\\ SA=6s~~\begin{cases} s=&length~of\\ &a~side\\ \cline{1-2} s=&30 \end{cases}\implies SA=6(30)\implies SA=180](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cube%7D%5C%5C%5C%5C%20V%3Ds%5E3~~%20%5Cbegin%7Bcases%7D%20s%3D%26length~of%5C%5C%20%26a~side%5C%5C%20%5Ccline%7B1-2%7D%20V%3D%2627000%20%5Cend%7Bcases%7D%5Cimplies%2027000%3Ds%5E3%5Cimplies%20%5Csqrt%5B3%5D%7B27000%7D%3Ds%5Cimplies%2030%3Ds%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ctextit%7Bsurface%20area%20of%20a%20cube%7D%5C%5C%5C%5C%20SA%3D6s~~%5Cbegin%7Bcases%7D%20s%3D%26length~of%5C%5C%20%26a~side%5C%5C%20%5Ccline%7B1-2%7D%20s%3D%2630%20%5Cend%7Bcases%7D%5Cimplies%20SA%3D6%2830%29%5Cimplies%20SA%3D180)
Answer:
C-2
Step-by-step explanation:
Answer:
f(w) = 3w + 2,000,000/w
Step-by-step explanation:
We know that the area of a rectangle is the product of its length and width:
A = LW
Filling in the given values lets us write an expression for the length of the field.
1,000,000 = Lw
L = 1,000,000/w
Since there are 3 fences of length w and two of length L, the total perimeter fence length is the sum ...
f(w) = 3w + 2(1,000,000)/w
Combining the constants, we have a function for the perimeter fence length in terms of the width of the field:
f(w) = 3w +2,000,000/w
Answer:
5/8
Step-by-step explanation:
A T L A N T I C
8 letters, 3 vowels, 5 consonants
5 consonants out of 8 letters = 5/8
Answer:
12
Step-by-step explanation:
The range of a data set is just the difference between the largest and smallest values.
So, let's find the smallest value: it's 39. The largest value is 51.
Their difference is:
51 - 39 = 12
Thus, the answer is 12.
<em>~ an aesthetics lover</em>
