Answer:
56.3 kilometers per hour
Step-by-step explanation:
We know D = RT
where
D is distance
R is rate (speed)
T is time
Let's Bill's rate be "x". Thus using equation we can write:
D = xt
We know Eugene travelled 21.1 faster than Bill, so Eugene's rate is 21.1 + x. So we can write:
D = (21.1 + x)t
D = 21.1t + xt
Now, putting t = 1 in both since after 1 hour given, we have:
D = x(1)
D = x
and
D = 21.1(1) + x(1)
D = 21.1 + x
We know the sum of both the distance is 133.7, so we can write:
x + 21.1 + x = 133.7
Solving for x:
2x = 133.7 - 21.1
2x = 112.6
x = 112.6 / 2
x = 56.3 km/hr
This is Bill's rate: 56.3 kilometers per hour
Answer:
35 percent
Step-by-step explanation:
To solve this problem we multiply the amount by the percent and add them up to get the total amount times the percent
amount * percent + amount * percent = total amount * percent
4 * .20 + 12 * .40 = (4+12) * x
.8 + 4.8 = 16 x
Combine like terms
5.6 = 16x
Divide by 16
5.6/16 = 16x/16
.35 =x
35 percent
Number 2 is “division into zero property”
Number 3 is “identify property of division”
Number 4 is “-48xy”
A point (-0.8, 0.6) will be a point on the unit circle in the second quadrant. Since it is a unit circle, its radius is 1, and we have
sin(α) = y = 0.6
cos(α) = x = -0.8
tan(α) = y/x = 0.6/-0.8 = -0.75
The angle is α = arccos(-0.8) ≈ 143.13°
______
For the unit circle, the trig values are always the coordinates or their ratio as shown above, regardless of quadrant.
