Question

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Answer 1

$\bf \textit{using the pythagorean theorem}\\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}\qquad \begin{cases} c=hypotenuse=x\\ a=adjacent=12\\ b=opposite=12\\ \end{cases} \\\\\\ x=\sqrt{12^2+12^2}\implies x=\sqrt{288}\implies x=\sqrt{12^2\cdot 2} \\\\\\ x=12\sqrt{2}$