-28; 200•.04
-fewer than expected
Answer: (-4,0), (4,0)
Step-by-step explanation:
unit test lm ao
Answer:
<h2>
<u>49.34</u></h2>
Step-by-step explanation:
986.99/20=49.3485
Divide 986.99 by 20 which gets you 49.3485 then just around up the 10.
Hope this helps! Have a great day. Remember your amazing and you got this! Alycia <3
To solve this problem, we make use of the z statistic. The
formula for z score is:
z = (x – μ) / s
where,
x = is the sample score = 21 or higher
μ = the population mean = 20.8
s = the standard deviation = 4.8
Solving for the z score:
z = (21 – 20.8) / 4.8
z = 0.0417
Next step to do is to find for the p value using the
standard distribution tables at z = 0.04. Since we are looking for the
probability of getting 21 or higher, therefore this is a right tailed test,
hence
p = 0.516
<span>So there is about 51.6% that a student will get a score of
21 or greater.</span>
Answer:
The answer is below
Step-by-step explanation:
The question is not complete. A complete question is in the form:
A letter is chosen at random from the letters of the word EXCELLENT. Find the probability that letter chosen is i) a vowel ii) a consonant.
Solution:
The total number of letters found in the word EXCELLENT = 9
i) The number of vowel letters found in the word EXCELLENT = {E, E, E} = 3
Hence, probability that letter chosen is a vowel = number of vowels / total number of letters = 3 / 9 = 1 / 3
probability that letter chosen is a vowel = 1/3 = 0.333 = 33.3%
ii) The number of consonant letters found in the word EXCELLENT = {X, C, L, L, N, T} = 6
Hence, probability that letter chosen is a consonant = number of consonant / total number of letters = 6 / 9 = 2 / 3
probability that letter chosen is a consonant = 2/3 = 0.667 = 66.7%
