Question

Which shows the correct substitution of the values a, b, and c from the equation 1 = –2x + 3x2 + 1 into the quadratic formula? Quadratic formula: x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction x = StartFraction negative (negative 2) plus or minus StartRoot (negative 2) squared minus 4 (3)(0) EndRoot Over 2(3) EndFraction x = StartFraction negative (negative 2) plus or minus StartRoot (negative 2) squared minus 4 (3)(2) EndRoot Over 2(3) EndFraction x = StartFraction negative (negative 2) plus or minus StartRoot (negative 2) squared minus 4 (3)(1) EndRoot Over 2(3) EndFraction x = StartFraction negative 3 plus or minus StartRoot 3 squared minus 4 (negative 2)(0) EndRoot Over 2(negative 2) EndFraction

Answer 1

First of all, you have to manipulate the equation into the standard

$ax^2+bx+c=0$

form. You can simplify the 1's on both sides and you have

$3x^2-2x=0$

This means that your coefficients are

$a=3,\quad b=-2,\quad c=0$

And since the solving formula is

$x_{1,2}=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

Plugging your values yields

$x_{1,2}=\dfrac{-(-2)\pm\sqrt{(-2)^2-4\cdot 3\cdot 0}}{2\cdot 3}$

Answer 2

Answer:

the answer is A