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3 years ago

Evaluate. (34 + 14) ÷ [42 – (20 + 16)]

Mathematics

2 answers:

ss7ja [257]3 years ago

8 0

8 is the answer ................

Alex787 [66]3 years ago

5 0

48 ÷ (42 - 36) =
<span>48 ÷ 6 </span>
<span>answer = 8

</span>

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A rectangular table has an area of 5/6 of a square meter. The length of a table is 2/3 of a meter. What is the width of the tabl

sergejj [24]

Answer:

Width is $1 \frac{1}{4} m$ or 1.25m

Step-by-step explanation:

$\frac{5}{6}$ ÷ $\frac{2}{3}$ = 5/6 x 3/2 = 5/4

6 0

3 years ago

g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa

adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is $\sigma = 0.0133$

Step-by-step explanation:

From the question we are told that

The upper specification is $USL = 1.68 \ mm$

The lower specification is $LSL = 1.52 \ mm$

The sample mean is $\mu = 1.6 \ mm$

The standard deviation is $\sigma = 0.03 \ mm$

Generally the capability index in mathematically represented as

$Cpk = min[ \frac{USL - \mu }{ 3 * \sigma } , \frac{\mu - LSL }{ 3 * \sigma } ]$

Now what min means is that the value of CPk is the minimum between the value is the bracket

substituting value given in the question

$Cpk = min[ \frac{1.68 - 1.6 }{ 3 * 0.03 } , \frac{1.60 - 1.52 }{ 3 * 0.03} ]$

=> $Cpk = min[ 0.88 , 0.88 ]$

$Cpk = 0.88$

Now from the question we are asked to evaluated the value of standard deviation that will produce a capability index of 2

Now let assuming that

$\frac{\mu - LSL }{ 3 * \sigma } = 2$

$\frac{ 1.60 - 1.52 }{ 3 * \sigma } = 2$

=> $0.08 = 6 \sigma$

=> $\sigma = 0.0133$

$\frac{ 1.68 - 1.60 }{ 3 * 0.0133 }$

=> $2$

Hence

$Cpk = min[ 2, 2 ]$

$Cpk = 2$

So $\sigma = 0.0133$ is the value of standard deviation required

3 0

3 years ago

How do you figure out coordinates of a line if you only have the equation?

iren2701 [21]

Answer:

Step-by-step explanation:

u can figure the x and y intercepts by just the equation. U can also figure points by subbing.

example :

6x + 2y = 12......there are 2 ways to find the y intercept....u can either sub in 0 for x and solve for y....or u can put the equation in y = mx + b form where b is ur y int.

y = mx + b form :

6x + 2y = 12

2y = -6x + 12

y = (-6/2)x + 12/2

y = -3x + 6.........so the y int is 6 or (0,6)

or u can sub in 0 for x and solve for y

6x + 2y = 12

6(0) + 2y = 12

2y = 12

y = 12/2

y = 6.........y int is 6....or (0,6)

==============================

to find the x intercept. sub in 0 for y and solve for x

6x + 2y = 12

6x + 2(0) = 12

6x + 0 = 12

6x = 12

x = 12/6

x = 2.....so ur x intercept is 2 or (2,0)

===============================

if u dont have a graph to look at to plot points using the slope, then u can easily sub in any number for x and find y to find points on ur line.

6x + 2y = 12.......pick any number for x...besides 0.....x = 1

6(1) + 2y = 12

6 + 2y = 12

2y = -6 + 12

2y = 6

y = 6/2

y = 3......so one point on this line is : (1,3)

6x + 2y = 12......when x = 2

6(2) + 2y = 12

12 + 2y = 12

2y = 12 - 12

2y = 0

y = 0......and another point is (2,0)

u can keep subbing in any number for x to find y....this will find points on ur line.

5 0

3 years ago

The diagonals of rectangle nopq intersect at point r. if oq=2(x+3) and pr=3x-5, solve for x.

OverLord2011 [107]

The diagonals of a rectangle are always congruent. We have the whole length of OQ to be 2x + 6, and we have only half of NP. Therefore, OQ = 2(PR). 2x+6=2(3x-5). 2x+6 = 6x-10. 16 = 4x so x = 4. That means that each diagonal is 14 units long.

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3 years ago

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If your equation us y equal 4x-5 then what does your table look like

attashe74 [19]

It looks like a straight line going up and crosses the y axis at -3

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3 years ago