The three numbers are 2, 5, and 11.
The sum of 3 numbers is 18. 2 + 5 + 11 = 18
Since the problem states that every number is a prime number, then the number must be a natural number greater than 1 that has no positive divisors other than 1 and itself.
2 / 1 = 2 OR 2 / 2 = 1 These numbers are prime numbers because their divisors
5 / 1 = 5 OR 5 / 5 = 1 are 1 and itself.
11/1 = 11 OR 11/11 = 1
Answer:
L 41/3 14 [200] G
Step-by-step explanation:
P = ( 2 / 3 )s;
s = ( 3 / 5 )t ;
p + s + t = 280 ;
Then, p =( 2 / 3 )( 3 / 5 )t ;
p = ( 2 / 5 )t;
We solve the equation : ( 2 / 5 )t + ( 3 / 5 )t + t = 280 ;
( 2 / 5 )t + ( 3 / 5 )t + ( 5 / 5 )t = ( 1400 / 5 )t;
10t = 1400 ;
t = 1400 ÷ 10 ;
t = 140 postcards has Tim;
p = ( 2 / 5 ) × 140 = 56 postcards has Paul;
s = ( 3 / 5 ) × 140 = 84 postcards has Shawn ;
Answer: B) 2(x+4)
Step-by-step explanation: Hope this help :D
Answer:
G-7×17=119
Step-by-step explanation:
A prime number is a number which has only two factors, 1 and itself.
A composite number on the other hand is any number that has more than two factors.
In the options
In F-5×15=75, 15 can still be decomposed into 5X3
In H-9×19=171, 9 can still be decomposed into 3X3
In J-11×21=231, 21 can still be written as 7X3.
So option G is the only equation which could show Brodricks work.
