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VladimirAG [237]
4 years ago
14

carmel can drive 320 miles on one tank of gas, and one tankful costs $39. how many tanks of gas will she need to drive 2,240 mil

es, and how much will it cost? use inverse operations to check your answer.
Mathematics
1 answer:
BARSIC [14]4 years ago
4 0

Answer:

She will need 7 tanks of gas. It will cost $273.

Step-by-step explanation:

First, we divide the amount of miles that she needs to go by the amount she can drive on one tank.

2240/320 = 7

She will need 7 tanks. Multiply the cost of one tank by 7.

$39*7 = $273

It will cost $273 total.

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What is the square root of 248 + square root of 63​
enyata [817]

Answer:

1) √248 = ± 15.7480157

2)√63 = ± 7.93725393

 

Step-by-step explanation:

7 0
3 years ago
describe the relationship between n and 4 that will make the value of the expression 7× n/4 greater than 7
Norma-Jean [14]
So set up an equation!

7* n/4 > 7

So trying to get the variable alone...

n/4 > (7/7) aka 1
n> 1*4
n> 4

Try it out!

7* 6/4 = 42/4 = 21/2= 10 and 1/2

It is greater than 7
7 0
4 years ago
Determine whether the number is a perfect square 47
Ghella [55]
Perfect squares are n² where n is a whole number
whole numbers are like 0,1,2,3,4,5,6, etc
no decimal or fractions

we can do that be looking at the perfect squares we know
2²=4
3²=9
4²=16
5²=25
6²=36
7²=49
8²=64
etc

so we see 47 is between 6² and 7²
therefor, for n²=47, n is between 6 and 7 and is therfore not a whole number
that makes 47 not a perfect square
7 0
4 years ago
Read 2 more answers
If 6=2x+4y, what is the value of x+2y?
Tamiku [17]

Answer:

3

Step-by-step explanation:

Take 2 as a common then divide by 2

6÷2 =3

6 0
3 years ago
11-Determine the specific heat of a material if a 12-g sample absorbed 96 J as it was heated from 20°C to 40°C. *
kompoz [17]

Answer:

c=0.4\ J/g^{\circ} C

Step-by-step explanation:

Given that,

Mass of a sample, m = 12 g

Heat absobed by the sample, Q = 96 J

It was heated from 20°C to 40°C.

We need to find the specific heat of a material. The heat absorbed by a sample is given by :

Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{96}{12\times (40-20)}\\\\=0.4\ J/g^{\circ} C

So, the specific heat of the material is 0.4\ J/g^{\circ} C.

3 0
3 years ago
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