Solve the compound inequality 3x+12 -9 and 9x-3 33
1 answer:
Solve each seperately
3x+12>-9
minus 12 both sides
3x>-21
divide by 3 both sides
x>-7
9x-3<33
add 3 both sides
9x<36
divide both sides by 9
x<4
so
x>-7 and x<4
-7<x<4
solution is all numbers betwee -7 and 4 not including -7 nor 4
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