Answer:
B
Step-by-step explanation:
4x²/2 √x^4/4x²
2x²√x²/4 ( equal to C)
4x²/2(x²/2x)
2x²(x²/2x)=
2x^4/2x =x³ ( equal to A) or √x^6 ( equal to D) also E x²√x²=x^3
Answer:
f(x)=−4(x+ 41 ) 2 − 4 11
Explanation:
The given function is
f(x) = - 4 {x}^{2} - 2x - 3f(x)=−4x 2 −2x−3
To write the function is vertex form, we need to complete the square.
We first factor -4 to get:
f(x) = - 4 ({x}^{2} + \frac{1}{2} x) - 3f(x−4(x2 + 21 x)−3
Add and subtract the square of half the coefficient of x.
f(x) = - 4( {x}^{2} + \frac{1}{2} x + \frac{1}{16} ) - \frac{1}{4} - 3f(x)=−4(x 2 + 21 x+ 16 1 )− 41 −3
We factor the perfect square trinomial and simplify to get:
f(x) = - 4( {x + \frac{1}{4} )}^{2} - \frac{11}{4}f(x)=−4(x+ 41 ) 2 − 4 11
1/4, 8/15, 6/5
One way to figure this out is to divide the fractions and find which number is bigger
Or you should know 1/4= .25 , 8/15 is around half or .5 and 6/5 the numerator is larger than the denominator, so it would be bigger than 1 <span />
Answer:
Answer choice B
Step-by-step explanation:
An algebraic expression to represent the value of this car after M months is y=Mx+C.
We have given that the
The straight-line depreciation equation for a car is,
y = -2,680x + 26,800.
therefore after 4moths
y = -2,680(4) + 26,800.
y = -10720 + 26,800.
y=16080
<h3>
What is the slope?</h3>
The slope of a line is a measure of its steepness. Mathematically, the slope is calculated as rise over run (change in y divided by change in x)
b. For find after the 75 months replace x by 75 and slolve the given inequality.
Suppose that M represents the length of time in months when
the car still has value.
An algebraic expression to represent the value of this car after M months.
y=Mx+C.
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