State the horizontal asymptote of the rational function.<br> f(x) = x^2 + 9x-9/x-9

How many milliequivalents of sodium chloride are contained with 3 L of normal saline?

AVprozaik [17]

Answer:

466mEq

Step-by-step explanation:

First, we need to know the concentration of NaCl in a normal saline solution, this is by definition 0.9%, meaning we have 0.9g of NaCl per 100ml of solution, we want to know how much NaCl we have in 3L (3000ml):

$3000ml*\frac{0.9g}{100ml}=27g=27000mg$

So, we have 27000mg in 3L of normal saline solution.

Now, acording to our milliequivalent (mEq) equation ( $mEq=\frac{mg}{pE}$ ) where pE is de molecular mass of NaCl divided by their charges, in this case 1:

$pE= \frac{23+35}{1}=\frac{58}{1} = 58$

Finally we substitute in the mEq formula:

$mEq=\frac{mg}{pE}=\frac{27000}{58}=466mEq$

I hope you find this information useful! Good luck!

4 0

2 years ago

Ramon earns $1,880 each month and pays $53.30 on electricity. To the nearest tenth of a percent, what percent of Ramon's earning

AfilCa [17]

<h2>Answer:</h2>

Each month, 2.8% Ramon's earnings are spent on electricity.

<h2>Step-by-step explanation:</h2>

You know, that 100 percent are his earnings - $1,880

Now, you need to find out, how much is 1%. You do that by dividing $1,880 by 100.

Now you have to divide the amount he pays on electricity - $53.3 by one percent of his earnings - $18.8

So, now you know, that he pays exactly 2.83511% of his earnings on electricity. But from assignment, you know, that it has to be rounded to the nearest tenth of a percent. The number is 2.8351. So we will round it to 2.8% ,because 3 is rounded down. (https://www.mathsisfun.com/rounding-numbers.html)

100% = $1,880

$1,880/100 = $18.8

$53.3/$18.8 = 2.83511

2.83511% ≈ 2.8%

3 0

2 years ago

Write an equation for an ellipse centered at the origin, which has foci at (\pm8,0)(±8,0)left parenthesis, plus minus, 8, comma,

mario62 [17]

Answer:

The equation of the ellipse is $\frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1$

Step-by-step explanation:

The standard form of the equation of an ellipse with center (0 , 0) is

$\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$ , where

The coordinates of the vertices are (± a , 0)

The coordinates of the foci are (± c , 0) , where c ² = a² - b²

∵ The ellipse is centered at the origin

∴ The center of it is (0 , 0)

∵ It has foci at (± 8 , 0)

- The coordinates of the foci are (± c , 0)

∴ c = ±8

∵ It has Vertices at (± 17 , 0)

- The coordinates of the vertices are (± a , 0)

∴ a = ±17

∵ c² = a² - b²

- Substitute the values of c and a to find b

∴ (8)² = (17)² - b²

∴ 64 = 289 - b²

- Add b² to both sides

∴ b² + 64 = 289

- Subtract 64 from both sides

∴ b² = 225

- Take √ for both sides

∴ b = ± 15

∵ The equation of the ellipse is $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$

- Substitute the values of a and b in it

∴ $\frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1$ ⇒ $\frac{x^{2}}{289}+\frac{y^{2}}{225}=1$

∴ The equation of the ellipse is $\frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1$

6 0

3 years ago

A function is represented by the graph.A function is represented by the graph. Complete the statement by selecting from the drop

8090 [49]

Answer:

= to because the graph has a y int at 1 and so does your formula given (just make x=0 to find it by plugging that in) and that one has a y int at 1 too

Step-by-step explanation:

3 0

3 years ago

Rewrite the following equation in exponential form.

ira [324]

Answer:

5² = 25

Step-by-step explanation:

log5 25 = 2

log(b) (x) = (y)

make b^(y) = (x)

5² = 25

I hope this helps!

5 0

2 years ago

State the horizontal asymptote of the rational function. f(x) = x^2 + 9x-9/x-9