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Jlenok [28]
3 years ago
8

Luke bought 256256256 ounces of strawberries. He divided them evenly between 888 different pies. How many pounds of strawberries

did Luke put into each pie?
Mathematics
1 answer:
SIZIF [17.4K]3 years ago
4 0

Answer:

2 pounds.

Step-by-step explanation:

We have been given that Luke bought 256 ounces of strawberries. He divided them evenly between 8 different pies. We are asked to find the pounds of strawberries that Luke put on each pie.

First of all, we will convert 256 ounces into pounds.

We know that 1 pound equals 16 ounces. To convert 256 ounces into pounds, we need to divide 256 by 16.

\text{256 ounces}=\frac{256}{16}\text{ pounds}=16\text{ pounds}

Now we will divide 16 pounds by 8 to find number of strawberries put on each pie.

\text{Pounds of strawberries on each pie}=\frac{16}{8}

\text{Pounds of strawberries on each pie}=2

Therefore, Luke put 2 pounds strawberries on each pie.

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Complete Question

Question: In the bronze medal game of the 2014 FIBA Asia Cup... In the bronze medal game of the 2014 FIBA Asia Cup, and with his team down by two points, Philippines guard Paul Dalistan was fouled while attempting a three-pointer at the buzzer. He missed the shot and headed to the line for three foul shots.

1. Watch the video of Dalistan preparing to take his first shot. Before he shoots, what is the probability that Philippines will win the game? Lose the game? Send it into overtime? Dalistan’s free throw percentage is 84.6%

Answer:

a

    The probability that Philippines will win the game is   P(A) =  0.6055

b

   The probability that Philippines will lose the game is P(B) =  0.00365

c

  The probability that the game will be sent to overtime  is P(C) =  0.06

Step-by-step explanation:

From the question we are told that

    The  probability of  Paul Dalistan making a shot is  p  =  0.846

   The probability of  Paul Dalistan not making the shot is  q =  1- p  =  1-  0.846=0.154

     Paul Dalistan team was down by two points

This mean that for Paul Dalistan's  team to win the game he must make the 3 free throws

So the probability that Philippines will win the game is mathematically represented as

    P(A) =   p^3

=>  P(A) =  0.846^3

=>  P(A) =  0.6055

Gnerally for Paul Dalistan's  team to loss the game it means that Paul Dalistan did not make any of the free shot

Hence the probability that Philippines will loss the game is  

     P(B) =  q^3

=>  P(B) =  (0.154 )^3

=>  P(B) =  0.00365

Generally for the game to be sent to overtime  then the game must be tied and for the game to be tied, Paul Dalistan have to make 2 out of the three shots

   Hence the probability that game will go to overtime is  

          P(C) =  3 *  0.846 *  0.154  *  0.154

         P(C) =  0.06

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