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3 years ago

The air temperature at 2 pm was 12º. What was the air temperature at 8 pm, if it had dropped 15ºby

Mathematics

2 answers:

Aloiza [94]3 years ago

5 0

Answer:

-3

Step-by-step explanation:

The answer would be -3, because if it were to go down 15 degrees from when it was 2 PM. The equation you would have to do is 12 - 15. Which answsering that would be -3

Elanso [62]3 years ago

4 0

Answer:

-3 degrees at 8 pm.

Step-by-step explanation:

That would be 12 - 15

= -3 degrees.

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3 years ago

the length of a rectangular parking lot at the airport is 2/3 mile.if the area is 1/2 square mile, what is the width of the park

olya-2409 [2.1K]

<h3>Answer:</h3>

3/4 mile

<h3>Explanation:</h3>

Area is the product of length and width. Put the given values into that formula and solve for width.

... A = L·W

... (1/2 mi²) = (2/3 mi)·W

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3 years ago

What is the equation of a hyperbola with a = 5 and c = 15? Assume that the transverse axis is horizontal.

gogolik [260]

Answer:

$\frac{x^2}{25} -\frac{y^2}{200} =1$

Step-by-step explanation:

Recall that the equation of hyperbola centered at the origin with transverse horizontal axis has the general form:

$\frac{x^2}{a^2} -\frac{y^2}{b^2} =1\\and\,\,\,\, with\\c=\sqrt{a^2+b^2}$

since we know that a = 5 ,and c = 15,we can solve for b:

$15=\sqrt{5^2+b^2} \\15^2=25+b^2\\b^2=200\\$

then the equation of the hyperbola becomes:

$\frac{x^2}{5^2} -\frac{y^2}{200} =1\\\frac{x^2}{25} -\frac{y^2}{200} =1$

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3 years ago

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3 years ago

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