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jok3333 [9.3K]
3 years ago
6

For the function y=3x^2-12x+4 , what’s the mirroring point for the y-intercept? (x,y) form please

Mathematics
1 answer:
Slav-nsk [51]3 years ago
4 0

Answer:

the you run y=3

Step-by-step explanation:

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BEEEP Hhh, Math sucks ;-;
Alex

Answer:

A is the answer.

Step-by-step explanation:

C=2πr

/2π /2π

C/2π=r

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What is the measure of ZBAQ<br> 1<br> B<br> 84<br> 0 x<br> 140
Dahasolnce [82]

Answer:

117.600

Step-by-step explanation:

7 0
3 years ago
The graphs of f(x) and g(x) are shown below:
Alekssandra [29.7K]

Your Answer: G(x) = (x − 5)²

I just finished my semester exam, and this was one of the questions. I guessed on this question because I had no clue of what the answer was, and lucky me, I got the question right :D

Hope this helps y'all with your test :)

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3 years ago
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How to write an equation for the line perpendiculer and trhough the given ppoint?
valentinak56 [21]
A method that always works is to find the slope of the given line, then find the negative reciprocal of that. Your result will be the slope of the perpendicular line. Using this slope and the given point, fill in the parameters of the point-slope form of the equation of a line.

For m = slope of given line and (h, k) = given point, the perpendicular line will be
  y = (-1/m)(x -h) +k

Often, this equation can be simplified to another appropriate form, such as slope-intercept form (y = mx+b) or standard form (ax+by=c).

_____
The slope of a given line can be found by solving its equation for y. The slope is the coefficient of x in that solution. If the given line is characterized by two points, (x1, y1) and (x2, y2), then its slope is m = (y2-y1)/(x2-x1).

In the unusual case where the given line is vertical (x=<some constant>), the slope of the perpendicular line is zero, and the line you want becomes y=k.
5 0
3 years ago
A bucket of paint has spilled on a tile floor. The paint flow can be expressed with the function p(t) = 6t, where t represents t
alukav5142 [94]
P(t)=6t

A(p)=πp^2, since p(t)=6t

A(t)=π(p(t))^2

A(t)=π(6t)^2

A(t)=36πt^2, so when t=8 and approximating π≈3.14

A(8)≈36(3.14)(8^2)

A(8)≈36(3.14)64

A(8)≈7234.56 u^2
3 0
3 years ago
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