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3 years ago

A bag with 8 marbles is shown below. A marble is chosen from the bag at random. What is the probability that it is grey?

Mathematics

1 answer:

GrogVix [38]3 years ago

4 0

Answer:

1/8 of a chance of getting a gray marble.

Step-by-step explanation:

Well if the bag has 8 marbles each marble is 1/8 of the bag.

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Help pleaseee! with geometry

8_murik_8 [283]

Answer:

2x(x+6)(x-6)

Step-by-step explanation:

2x³-72

2x(x²-36)

2x(x+6)(x-6)

5 0

3 years ago

Rewrite the following without an exponent<br> (-7)⁻²

chubhunter [2.5K]

Answer:

The correct answer is 1/49

Step-by-step explanation:

In order to find this, we first can eliminate the negative in the exponent by putting the whole this in the denominator.

(-7)^-2 = 1/(-7)^2

Now we can evaluate the denominator

1/(-7)^2 = 1/49

7 0

4 years ago

If The diameter of a circle is 14 yards.what is the circles circumference

amm1812

Answer:

14π yards^2, or 43.98^2 yards rounded to 2dp

Step-by-step explanation:

circumference = diameter x π

6 0

3 years ago

What is 9736 multiplied by 704

Orlov [11]

Answer:

9736 times 704 is 6854144

4 0

3 years ago

Read 2 more answers

A research firm needs to estimate within 3% the proportion of junior executives leaving large manufacturing companies within thr

Y_Kistochka [10]

Answer:

972 junior executives should be surveyed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

35% of junior executives left their company within three years.

This means that $\pi = 0.35$

0.95 = 95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

To update this study, how many junior executives should be surveyed?

Within 3% of the proportion, which means that this is n for which M = 0.03. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.35*0.65}{n}}$

$0.03\sqrt{n} = 1.96\sqrt{0.35*0.65}$

$\sqrt{n} = \frac{1.96\sqrt{0.35*0.65}}{0.03}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.35*0.65}}{0.03})^2$

$n = 971.2$

Rounding up:

972 junior executives should be surveyed.

5 0

3 years ago