Givens
Petri Dish A sees a double ever 10 minutes
Petri Dish B sees a double ever 6 minutes
Consequences
A doubles 60 / 10 = 6 times.
B doubles 60 / 6 = 10 times.
Solution
If you work best with numbers then suppose there are 100 bacteria in both dishes at the beginning
A = 100 * 2^6
B = 100 * 2^10
A will have 100 * 64 = 6400 bacteria growing inside A
B will have 100 * 1024 = 102400 bacteria growing inside B
B/A = 102400 / 6400 = 16
There are 16 times as many in B than in A. <<<< Answer
Answer:
28 minutes
Step-by-step explanation:
Dans computer reads 68% of battery left after 1 hour. This means that 1 hour is 68% of the computer's entire battery life.
Let the entire battery life be x (in hours). Hence:
Therefore:
=> x = 1.47 hrs = 1 hr 28 minutes
Hence, the entire battery life is 1 hr 28 minutes.
If 1 hour has elapsed, the remaining time left for his battery to provide power will therefore be:
1 hr 28 minutes - 1 hr = 28 minutes
His battery will provide power for 28 more minutes.
4. Cross multiply (10•6) (15•n) 15n=60 you do the opposite operation so instead of multiply 15•n you divided 15 from n. And what u do on one side u do on both. So divide 15 from 60 and u get 4.
Answer:
2.00000000e+100
Step-by-step explanation:
2
Step-by-step explanation:
lo siento much solo si fuera Buena con matimaticas.
