<span>For an independent-measures anova comparing four treatment conditions, dfbetween = 3.
TRUE.
The dfbetween is given by the number of treatments minus 1.
</span>
Answer:
- Josh's book lands first
- Ben's lands about 0.648 seconds later
Step-by-step explanation:
Using the given equation for v=60 and s=40, the height of Ben's book is ...
h(t) = -16t² +60t +40
We want to find t when h(t) = 0, so we're looking for the solution to ....
0 = -16t² +60t +40
Using the quadratic formula, we find the positive value of t to be ...
t = (-60 -√(60² -4(-16)(40)))/(2(-16)) = (15 +√385)/8 ≈ 4.3277
__
Similarly, the height of Josh's book is ...
0 = -16t² +48t +40
t = (-48 -√(48² -4(-16)(40)))/(2(-16)) = (12 +√304)/8 ≈ 3.6794
__
The time before Josh's book lands is shorter by ...
4.3277 -3.6794 ≈ 0.6482 . . . . . seconds
Josh's book reaches the ground first, by about 0.648 seconds.
We can’t really see the problem
Assume that,
adult = x
child = y
x+2y = 35 (1st equation)
2x+3y = 60 (2nd equation)
x = 35-2y (3rd equation)
Substitute 3 into 2 :
2(35-2y) + 3y =60
70-4y +3y = 60
y = 10
x+2y = 35
x+2(10) =35
x +20 =35
x = 15
One adult = $15