Answer:
It is 13.56
Step-by-step explanation:
You would have to divide 40.68 by 3. 3 goes 1 time into 4 so it is 10.
Around 90% of the time, you'll get joke answers or answers from bots. Even if I report their answers, they will report my question back? Even though their answers are completely irrelevant to my questions? Also, your moderators are probably 12 years olds, because why? THEY. DELETE. EVERY. CORRECT. ANSWER. I. MADE. Not to mention, that there are a bunch of other users that started grouping and bullied me with vulgar words. Disgusting. Is this what your moderating has become, Huh? Brainly? IS THIS WHAT YOU CALL A PEACEFUL FRIENDLY WEBSITE FOR EVERYONE? Shame on you, I will not use this website again, until you fix your moderation "ENTIRELY".
Yes it can and the answer would be 0.5
Terminating decimals are numbers that never stop going after the period. Such an example would be 10/3 which would give 3.333333 indefinitely. 1/2 gives a whole number, that is, 0.5
Answer:
Step-by-step explanation:
8 in × (1 ft)/(12 in) = ⅔ ft
36 ft × 58 ft × ⅔ ft = 1392 ft³
1392 ft³ × (1 yd³)/(27 ft³) ≅ 52 yd³
52 yd³ × $123/yd³ = $6396
Complete question:
Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby this mention is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect so the probability of a girl is 0.5. Assume that the group consists of 36 couples.
A) Find the mean and standard deviation for the number of girls in groups of 36 births.
B) Use the range rule of thumb to find the values separating results that are significantly low and significantly high.
C) Is the result of 33 girls significantly high? A result of 33 girls would suggest the method is effective or is not effective?
Answer:
a) mean = 18
Standard deviation =3
b) low range = 12
High range = 24
c) The result of 33 girls is significantly high. Yes, the method is effective.
Step-by-step explanation:
Given:
p = 0.5
n = 36
a) The mean is the product of n and p
Mean u = np
u = 36 * 0.5 = 18
The standard deviation is the square root of the product of n and p&q.
S.d ó = 


b) To find the range rule of thumb:
• For low range
Low range = u - 2ó
= 18 - (2 * 3)
= 12
• High range
= u + 2ó
= 18 + (2*3)
= 24
c) The result is significantly high, because 33 is greater than 24 girls.
A result of 33 girls would prove the method as effective.