Which equation is equivalent to the given equation? 13x=x2+42

How would you describe the difference between the graphs of f(x) = x^2 +4 and<br> g(y) - y^2 +4?

s2008m [1.1K]

Answer:

Step-by-step explanation:

The function $f(x)=x^2+4$ is a positive upwards opening parabola with the vertex at (0, 4), whereas

the function $g(y)=y^2+4$ is a positive rightwards opening parabola (sideways parabola) with the vertex at (4, 0). This means that answer to this is that g(y) is reflected over the x axis whereas f(x) is reflected over the y axis.

3 0

3 years ago

Problem #2: A piece of wood that is 15 feet long is out in half. Each half is then cut into twelve

garri49 [273]

Answer: Each peice of wood is equal to 0.625

Step-by-step explanation:

15/2 = 7.5

7.5/12 = 0.625

4 0

4 years ago

Morgan needs to order some new supplies for the restaurant where she works. The restaurant needs at least 650 glasses. There are

lukranit [14]

Answer:

43 Sets for 650

Step-by-step explanation:

3 0

3 years ago

Toxaphene is an insecticide that has been identified as a pollutant in the Great Lakes ecosystem. To investigate the effect of t

Likurg_2 [28]

Answer:

This data suggest that there is more variability in low-dose weight gains than in control weight gains.

Step-by-step explanation:

Let $\sigma_{1}^{2}$ be the variance for the population of weight gains for rats given a low dose, and $\sigma_{2}^{2}$ the variance for the population of weight gains for control rats whose diet did not include the insecticide.

We want to test $H_{0}: \sigma_{1}^{2} = \sigma_{2}^{2}$ vs $H_{1}: \sigma_{1}^{2} > \sigma_{2}^{2}$ . We have that the sample standard deviation for $n_{2} = 22$ female control rats was $s_{2} = 28$ g and for $n_{1} = 18$ female low-dose rats was $s_{1} = 51$ g. So, we have observed the value

$F = \frac{s_{1}^{2}}{s_{2}^{2}} = \frac{(51)^{2}}{(28)^{2}} = 3.3176$ which comes from a F distribution with $n_{1} - 1 = 18 - 1 = 17$ degrees of freedom (numerator) and $n_{2} - 1 = 22 - 1 = 21$ degrees of freedom (denominator).

As we want carry out a test of hypothesis at the significance level of 0.05, we should find the 95th quantile of the F distribution with 17 and 21 degrees of freedom, this value is 2.1389. The rejection region is given by {F > 2.1389}, because the observed value is 3.3176 > 2.1389, we reject the null hypothesis. So, this data suggest that there is more variability in low-dose weight gains than in control weight gains.

8 0

3 years ago

Calculate the chance of dice rolling the same time every roll

lilavasa [31]

I think it would be a one i eight chance of that happening 1/8

4 0

3 years ago