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Kaylis [27]
3 years ago
6

The ratio of the length of the corresponding sides of two rectangles is 5:8. The area of the smaller rectangle is 130 m2. To the

nearest whole number, what is the area of the larger rectangle?
Mathematics
2 answers:
marusya05 [52]3 years ago
7 0

Answer:

Area of the larger rectangle = 332.8 m²

Step-by-step explanation:

Ratio of the corresponding sides of two rectangles is 5 : 8 and the area of smaller rectangle is 130 m²

We have to calculate the area of larger rectangle.

Let length of two rectangles are L and L' and width be W and W'.

Now as given in the question

L/L' = 5/8 and W/W' = 5/8

Therefore ratio of two rectangles = A/A' = (L×W)/(L'×W') = (L/L')×(W/W') = (5/8)×(5/8) = (5/8)²

A/A' = (5/8)² = 130/A'

A' = 130× (8/5)² = (130×64)/25 = 332.8 m²

xxMikexx [17]3 years ago
5 0
I think the answer is 332.8 cm^2

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(2,2)

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A hypothetical population consists of eight individuals ages 13, 14, 17, 20, 21, 22, 24, & 30 years.
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Complete Question

A hypothetical population consists of eight individuals ages 13 14 17 20 21 22 24 30 years.  

A: what is the probability that a person in this population is a teenager?  

B: what is the probability of selecting a participant who is at least 20 years old?

We have that  probability that a person in this population is a teenager and probability of selecting a participant who is at least 20 years old is

From the question we are told

A hypothetical population consists of eight individuals ages 13, 14, 17, 20, 21, 22, 24, & 30 years.

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a)

Generally the equation for the  probability that a person in this population is a teenager   is mathematically given as

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b)

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