The ratio of the length of the corresponding sides of two rectangles is 5:8. The area of the smaller rectangle is 130 m2. To the

Question

3 years ago

6

nearest whole number, what is the area of the larger rectangle?

2 answers:

marusya05 [52] · Answer 1 · 2022-03-03T11:30:31+03:00

Answer:

Area of the larger rectangle = 332.8 m²

Step-by-step explanation:

Ratio of the corresponding sides of two rectangles is 5 : 8 and the area of smaller rectangle is 130 m²

We have to calculate the area of larger rectangle.

Let length of two rectangles are L and L' and width be W and W'.

Now as given in the question

L/L' = 5/8 and W/W' = 5/8

Therefore ratio of two rectangles = A/A' = (L×W)/(L'×W') = (L/L')×(W/W') = (5/8)×(5/8) = (5/8)²

A/A' = (5/8)² = 130/A'

A' = 130× (8/5)² = (130×64)/25 = 332.8 m²

xxMikexx [17] · Answer 2 · 2022-03-03T10:00:45+03:00

5 0

I think the answer is 332.8 cm^2